How many meters is 16 microns? Use scientific notation!

How many meters is 16 microns? Use scientific notation!

16 μ M = 16 × 10 ^ (- 3) mm = 16 × 10 ^ (- 6) M = 1.6 × 10 ^ (- 5) M

|What is the minimum value of X + 1 | - 6______ , X2009=______ ．

When ∵ | x + 1 | ≥ 0, | x = - 1, | x + 1 | - 6 has the minimum value of - 6, when x = - 1, X2009 = - 1

If X & # 178; + X + 1 = 0, find the value of the seventh power of X + twice the sixth power of X + the fifth power of X + the fourth power of X + the third power of X + the second power of X
On the test paper of lesson practice

x²+x+1=0,
Then: X & # 178; + x = - 1
The seventh power of X + twice the sixth power of X + the fifth power of X + the fourth power of X + the third power of X + the quadratic value of X
=x^5(x²+x)+x^4(x²+x)+x²(x²+x)+x²
=-x^5-x^4-x²+x²
=-x³(x²+x)
=x³
Because X & # 179; - 1 = (x-1) (X & # 178; + X + 1) = 0
So: X & # 179; = 1
So, the original formula is 1

In the polynomial 6a-2a3x3y-8 + 4x5, the coefficients and constants of the highest order terms are ()
A. 2 and 8b. 4 and - 8C. 6 and 8D. - 2 and - 8

In the polynomial 6a-2a3x3y-8 + 4x5, the coefficients and constants of the highest order terms are - 2, - 8, respectively

When 0 ≤ m ≤ 1, 2x-1 ＜ m (X & # 178; - 1) is constant, and the value range of real number x is obtained
RT

Let's first analyze the following ideas. We should try our best to separate the parameters of the constant establishment problem. This problem can separate the parameters, but we need to discuss the symbol of x ^ 2-1, which is also the key to this problem
(1) If x ^ 2-1 = 0, then x = 1 or - 1. When x = 1, the inequality becomes 11 or X (2x-1) / (x ^ 2-1) holds. So (2x-1) / (x ^ 2-1) 0, so the solution is X1 or X

It is known that a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of X is 1. Find the value of: - [(a + b) + CD] X

∵ a, B are opposite to each other, ∵ a + B = 0, ∵ C, D are reciprocal to each other, ∵ CD = 1, ∵ x = ± 1, ∵ when x = 1, [(a + b) + CD] x = - [0 + 1] × 1 = - 1; when x = - 1, [(a + b) + CD] x = - [0 + 1] × (- 1) = 1

Given that a and B are opposite numbers, C and D are reciprocal numbers, and the absolute value of X is 1, then (1-x) △ CD + (a + B + CD) X

From the question a + B = 0 CD = 1 x = + 1 or - 1
1-x）÷cd+(a+b+cd)x
When x = 1, (1-x) △ CD + (a + B + CD) x = 0 + 1 = 1
When x = - 1, (1-x) △ CD + (a + B + CD) x = 2 + (- 1) = 1

Given that a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of X is 4, try to find the value of X - (a + B + CD) + |a + B-5 | + |2-cd |

Because AB is opposite to each other, their sum is 0
Because CDs are reciprocal, their product is 1
Because the absolute value of X is 4, x = 4 or - 4
When x = 4,
x-(a+b+cd)+[a+b-5]+[2-cd]
=4-1+(-5)+1
=-1
When x = - 4,
x-(a+b+cd)+[a+b-5]+[2-cd]
=-4-1+(-5)+1
=-9

If the absolute values of two numbers are equal, then the two numbers are equal?

If two numbers are equal, the absolute values of the two numbers are equal
If the absolute values of two numbers are equal, then the two numbers are equal or opposite to each other

If the absolute values of two numbers are equal, then the two numbers are also equal______ Judge right or wrong

The absolute values of two numbers which are opposite to each other are equal, but the two numbers are not equal