Given y = (radical 2x-1) + (radical 1-2x) + half, find the value of one part of X + one part of Y
√(2X-1) √(1-2X)
Because the radical must be greater than or equal to 0, so
2X-1≥0
1-2X≥0
So, 1-2x = 0, x = 1 / 2
Y=0+0+1/2=1/2
1/X+1/Y=4
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