（1）3^2009-3^2008 （2）（-2）^101+（-2）^100 Because I didn't grasp the skills... So I need someone to click

（1）3^2009-3^2008 （2）（-2）^101+（-2）^100 Because I didn't grasp the skills... So I need someone to click

（1）3^2009-3^2008=3^2008×(3-1)=2×3^2008
（2）（-2）^101+（-2）^100=(-2)^100×(-2+1)=-2^100

1, the 11th power of 31 and the 14th power of 17 compare the size, 2, the square of factoring factor (A's Square - B's Square - C's Square) - the square of 4A's square C's Square

The 11th power of 31 multiplied by 31 can be written as the 12th power of 31, the 14th power of 17 multiplied by 17 can be written as the 15th power of 17, the 12th power of 31 can be written as the 4th power of 31, the 15th power of 17 can be written as the 5th power of 17, the 5th power of 17 is larger, that is, the 12th power of 31 is smaller than that of 17

The rope hanging on the flagpole is vertical, and it will be more than 1 meter after touching the ground. Straighten the rope so that the end of the rope just touches the ground. At this time, the distance between the touch point and the bottom of the flagpole is 5 meters. Calculate the height of the flagpole

If the flagpole height is x, the rope length is x + 1
Then x ^ 2 + 5 ^ 2 = (x + 1) ^ 2 Pythagorean theorem
X^2+5^2=X^2+2X+1
X=(25-1)/2
=12
So the flagpole is 12 meters high