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6 (X & sup2; - 2x + 1) / the third power of X - 3x & sup2; + 3x-1, this topic is written in the form of fraction, but I can't type out the fraction, please forgive me, ask to find out the integer value of X when the value of this fraction is an integer, please write the process of solving the problem, the answer is useless, I'm going to school tomorrow, please write how to simplify the denominator,
For denominator x ^ 3-3x ^ 2 + 3x-1 = (x ^ 3-x ^ 2) - 2 (x ^ 2-x) + (x-1) = x ^ 2 (x-1) - 2x (x-1) + (x-1) (common factor x-1) = (x-1) (x ^ 2-2x + 1) = (x-1) * (x-1) ^ 2 = (x-1) ^ 3, so the original formula = 6 (x-1) ^ 2 / (x-1) ^ 3 = 6 / (x-1), discuss
As shown in the figure, in quadrilateral ABCD, ∠ B = ∠ C, ab = DC, and ab is not parallel to DC. Is quadrilateral ABCD isosceles trapezoid? Why? [the figure is almost isosceles trapezoid]
Please explain the process. It's better to attach reasons after the process, OK
Make de ‖ ab
Then, Deb = ∠
∵∠C=∠B
∴∠DEC=∠C
∴DE=DC
∵AB=DC
∴AB=DE
The abed is a parallelogram
∴AD‖BC
∵ AB does not run on CD
The quadrilateral ABCD is an isosceles trapezoid
What is the square of (root sign) (2x) - the square reduction of X
=(root) 3 x
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