The square of the root sign (2x) - how much is the square of X? 2x is connected, not twice the square of X,

The square of the root sign (2x) - how much is the square of X? 2x is connected, not twice the square of X,

Original formula = √ (4x & sup2; - X & sup2;)
=√(3x²)
=√3×√x²
=√3|x|
|X | denotes the absolute value X

The process and answer to a math problem in grade two
a. B and C are the three sides of △ ABC, and (x + a) (x + b) + (x + b) (x + C) + (x + C) (x + a) = 0 has two equal real roots. Try to judge the shape of △ ABC
There must be a process
Thank you

x+a)(x+b)+(x+b)(x+c)+(x+c)(x+a)=0
The expansion is 3x ^ 2 + 2 (a + B + C) x + (AB + BC + AC) = 0
Because there are two equal real roots
So the discriminant = 4 (a + B + C) ^ 2-12 (AB + BC + AC) = 0
That is, (a + B + C) ^ 2 = 3 (AB + BC + AC)
The expansion is a ^ 2 + B ^ 2 + C ^ 2 = AB + BC + AC
The formula is two times two
(a-b)^2+(b-c)^2+(c-a)^2=0
So a = b = C is an equilateral triangle

Solving equation (formula method)
7x² - √6X - 5 = 0

X=｛√6±√[（√6）²-4×7×(-5)]｝/(2×7)
X=｛√6±√(6+140)｝/14
X=(√6±√146)/14
X=(√6±√146)/14
X1=(√6+√146)/14
X2=(√6-√146)/14