If there is a planet whose average distance from the sun is 8 times of that from the earth to the sun, then the cycle of the planet around the sun is What is the revolution period of the earth

If there is a planet whose average distance from the sun is 8 times of that from the earth to the sun, then the cycle of the planet around the sun is What is the revolution period of the earth

Kepler's third law (periodic law): the ratio of the third power of the semimajor axis of the orbits of all planets to the second power of the revolution period is equal
The formula is: A ^ 3 / T ^ 2 = K
A = semi major axis of planetary orbit
T = planetary revolution period
a^3/T^2＝（8a）^3/x^2
624 years
The revolution of the earth takes one year

High school physics problem, someone found an asteroid, measured its average distance to the sun is eight times the earth to the sun, to find the planetary revolution time

Use Kepler's third law (periodic law): the ratio of the third power of the semimajor axis of the orbits of all planets to the second power of the revolution period is equal
The formula is: R ^ 3 / T ^ 2 = K
The result is: 16 times root 2

The ratio of the earth's cycle around the sun to the moon's cycle around the earth is p, and the ratio of the earth's orbit radius around the sun to the moon's orbit radius around the earth is Q. the mass ratio of the sun to the earth can be obtained

GMm/r^2=m*4π^2/T^2*r
The result of the transfer is as follows:
M=4π^2*r^3/(T^2*G)
The two are comparable
M day: m land = P ^ 3 / Q ^ 2