0.9kg ice melts into water, which reduces the volume by 0.1m3
The volume of 0.9 kg water is 0.9 cubic decimeter, so the original volume of ice is 0.9 + 0.1 = 1 cubic decimeter
Ice density = 0.9 / (0.9 + 0.1) = 0.9/1 = 0.9 kg / cubic decimeter
A wooden block with a density of 0.6 × 103kg / m3 and a volume of 100cm3 is gently put into a bucket filled with water to calculate: (1) the volume of the wooden block above the water surface; (2) the mass of the overflow water
(1) Therefore, the volume of the block above the water surface: V exposure = (1-35) v = 25 × 100cm3 = 40cm3; (2) the gravity of the block: g = mg = ρ VG = 0.6 × 103kg / m3 × 100 × 10-6cm3 × 9.8n/kg = 0.588n ∵ the floating of the block ∵ f floating = g = 0.588n; according to Archimedes' principle, the gravity of draining water is equal to buoyancy, that is, g row = 588n A: (1) the volume of wood block above the water surface is 40cm3; (2) the mass of overflow water is 60g
When 100 cm3 ice melts into water, the following statement is correct (ρ ice = 0.9 × 103 & nbsp; kg / m3) ()
A. Mass 90g, water volume 90cm3b. Mass 100g, water volume 90cm3c. Mass 90g, water volume 100cm3d. Mass 90g, water density 0.9g/cm3
∵ ρ = MV, the mass of ice is m ice = ρ ice, V ice = 0.9g/cm3 × 100cm3 = 90g; ∵ ice melts into water, the state changes, the mass remains unchanged, ∵ m water = m ice = 90g; the volume of water is v water = m water, ρ water = 90g1g / cm3 = 90cm3