0.9kg ice melts into water, which reduces the volume by 0.1m3

0.9kg ice melts into water, which reduces the volume by 0.1m3

The volume of 0.9 kg water is 0.9 cubic decimeter, so the original volume of ice is 0.9 + 0.1 = 1 cubic decimeter
Ice density = 0.9 / (0.9 + 0.1) = 0.9/1 = 0.9 kg / cubic decimeter

A wooden block with a density of 0.6 × 103kg / m3 and a volume of 100cm3 is gently put into a bucket filled with water to calculate: (1) the volume of the wooden block above the water surface; (2) the mass of the overflow water

(1) Therefore, the volume of the block above the water surface: V exposure = (1-35) v = 25 × 100cm3 = 40cm3; (2) the gravity of the block: g = mg = ρ VG = 0.6 × 103kg / m3 × 100 × 10-6cm3 × 9.8n/kg = 0.588n ∵ the floating of the block ∵ f floating = g = 0.588n; according to Archimedes' principle, the gravity of draining water is equal to buoyancy, that is, g row = 588n A: (1) the volume of wood block above the water surface is 40cm3; (2) the mass of overflow water is 60g

When 100 cm3 ice melts into water, the following statement is correct (ρ ice = 0.9 × 103 & nbsp; kg / m3) ()
A. Mass 90g, water volume 90cm3b. Mass 100g, water volume 90cm3c. Mass 90g, water volume 100cm3d. Mass 90g, water density 0.9g/cm3

∵ ρ = MV, the mass of ice is m ice = ρ ice, V ice = 0.9g/cm3 × 100cm3 = 90g; ∵ ice melts into water, the state changes, the mass remains unchanged, ∵ m water = m ice = 90g; the volume of water is v water = m water, ρ water = 90g1g / cm3 = 90cm3