8g oxygen______ 1 mol & nbsp______ Mol electron

8g oxygen______ 1 mol & nbsp______ Mol electron

The amount of 8G oxygen = 8g32g / mol = 0.25mol, each oxygen molecule contains 16 electrons, and the amount of electronic substances is 16 times that of oxygen, so the amount of electronic substances in 0.1mol oxygen = 0.1mol × 16 = 1.6mol, so the answer is: 0.25; 1.6

0.1mol oxygen has () mol electrons

There are eight electrons outside one oxygen nucleus and two O atoms in one O2 molecule
So 0.2 * 8 = 1.6

How to calculate the total number of moles in 0.1mol oxygen

Oxygen chemical formula O2
One o contains eight electrons
So an O2 molecule has 8 * 2 = 16 electrons
So 0.1mol O2 has 0.1 * 16 = 1.6mol electrons

A single cylinder four stroke diesel engine consumes 200 grams of diesel per minute, and does 2.6 × 10 (6 power) J of useful work to find out the efficiency of the diesel engine?
The calorific value is 4.3x10 to the 7th power J / kg

Efficiency = 2.6 / (0.2 * 43) = 0.3023 = 30.23%

When a diesel engine with an efficiency of 40% outputs 3.44 × 107j of active power, what is the mass of diesel consumed? () (calorific value of diesel oil is 4.3 × 107 J / kg)
A. 0.8kgB. 2kgC. 0.32kgD. 2.8kg

∵ η = w useful q-release, q-release = w useful η = 3.44 × 107j40% = 8.6 × 107j, M = q-release, q = 8.6 × 107j4.3 × 107j / kg = 2kg

A diesel vehicle consumes 0.25kg diesel per minute, and the engine output power is 8.5 * 10 fourth power W. what is the efficiency of the diesel engine?
The calorific value of diesel oil is the 7th power of 4.3 × 10

Heat released by diesel consumed per minute: q = MQ = 0.25kg x 43000000j / kg = 10750000j
Work done by diesel engine per minute: w = Pt = 85000w x 60s = 5100000j
Efficiency of diesel engine: η = w / Q = 5100000j △ 10750000j = 47.4%

If 1kg diesel is used to supply 30% efficiency diesel engine, it can make the diesel engine more efficient
How much heat can be released by completely burning 1kg diesel oil? If 1kg diesel oil is supplied to a diesel engine with an efficiency of 30%, and the diesel can work for 30min, what is the output power of the diesel engine? (the calorific value of the diesel engine is 3.3 × 10 7J / kg)

(1)Q=q×m=3.3×10^7J/Kg×1Kg=3.3×10^7J
(2) 30% q = q suction = 9.9 × 10 ^ 6J
P = q suction / T = 9.9 × 10 ^ 6J / S = 5500w

The thermal efficiency of a diesel engine is higher than that of B diesel engine
If the efficiency of a diesel engine is higher than that of B diesel engine, then
A diesel engine consumes less diesel than B diesel engine
The power of B a diesel engine is higher than that of B
When C does the same work, the diesel consumed by a diesel engine is less than that consumed by B diesel engine
D can't judge

The answer is C
The efficiency of a heat engine is equal to the ratio of the mechanical work produced and the internal energy consumed. The higher the efficiency is, the same work is produced and the less fuel is consumed

If the mechanical efficiency of diesel engine is 40%, the useful work of 50 kg diesel oil is diesel oil, and the calorific value of diesel oil is 4.3 × 107 J / kg
But many of the answers are 8.6 million

Because heat = fuel mass × calorific value
Therefore, the heat released from full combustion of 50kg diesel oil is as follows:
50kg×4.3×10^7J/kg=2.15×10^9 J
Because active work = total work × mechanical efficiency
Therefore, we have made great efforts to:
2.15×10^9J×40%=8.6×10^8 J
A: the active work is 8.6 × 10 ^ 8 J

Hot engine test ~ diesel engine
The flywheel rotates for two cycles after a stroke of diesel engine. When the speed of a diesel engine is 1800r / min, the engine completes a power stroke within 1s

Fill in the blanks:
four
fifteen
Don't say the first empty one
The second empty calculation process is as follows
The number of turns of flywheel in 1 second is 1800 / 60 = 30
If the flywheel has two strokes per revolution, the stroke for 30 revolutions is 30 * 2 = 60
There is one work stroke in every four strokes, so the number of work strokes in 60 strokes is: 60 / 4 = 15