Given that f (x) = 2x & # 178; + BX + C, the solution set of the inequality f (x) < 0 is the analytic expression of (0,5) for f (x)

According to the relationship between root and coefficient, it is concluded that: 1
0+5=-b/2
0*5=c/2
The solution is: B = - 10, C = 0
f(x)=2x^2-10x

It is known that the solution of the inequality ax square + BX + C greater than - 2x is 1 less than x less than 3,
(1) If the equation AX square + BX + C + 6A = 0 has two equal roots, find the analytic formula of y = ax square + BX + C
(2) If the maximum value is a positive number, find the value range of A

ax+(b+2)x+c>0,1

The solution set of X-2 of the square-2x-24 of inequality x is?

I'm sorry, you're not inequality
If the inequality is: X-2 of the square of x-2x-24 > 0
Then (X-2) / [(X-6) (x + 4)] > 0
The solution set is: x > 6, or - 4

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