If the solutions of the linear inequality 4x + A / 3 > 1 about X are all the solutions of the linear inequality 2x + 1 > 0, then the value range of a is

2X + 1 > 0, x > negative half
4X+a/3＞1
4X+a＞3
When x ＞ 1 / 2, a ＜ 5

Solution equation: 3 (2x + 5) = 2 (4x + 3) + 1

Remove the brackets, 6x + 15 = 8x + 6 + 1, transfer the term, 6x-8x = 6 + 1-15, merge the similar terms, - 2x = - 8, coefficient into 1, x = 4

If integers x and y satisfy that the square of X + the square of Y + 2 is less than or equal to 2x + 2Y, find the value of X + y

Transference
That is, (X & # 178; - 2x + 1) + (Y & # 178; - 2Y + 1)

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