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Solving inequality: 1-x square + 6x > 0
1-x square + 6x > 0
X squared - 6x - 1 < 0
(x-3)(x+2)＞0
x＞3
x
The square of X - 6x + 4
The square of X - 6x + 4
The solution set of inequality-6x2-x + 2 ≤ 0 is ()
A. {x | x ≤ − 23} B. {x | x ≥ 12} C. {x | x − 23 ≤ x ≤ 12} D. {x | x ≤ − 23 or X ≥ 12}
From the inequality - 6x2-x + 2 ≤ 0, 6x2 + X-2 ≥ 0 is obtained, that is, (3x + 2) (2x-1) ≥ 0, and the solution is x ≤ − 23 or X ≥ 12. Therefore, the solution set of the original inequality is {x | x ≤ − 23 or X ≥ 12}
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