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Will (2-3x) + (3x-2) square = 0 be factorized
(2-3x) + (3x-2) square = 0 (3x-2) [- 1 + (3x-2)] = 0 (3x-2) (3x-3) = 0 x = 2 / 3 or x = 1
How to solve this one variable quadratic inequality
Please write down the origin of the steps, how to get the next step, why to get the next step,
x²-x+2
How to solve the problem that the square of x plus 2x minus 3 is greater than or equal to 0
It can be factorized first
x²+2x-3
=(x+3)(x-1)
therefore
(x+3)(x-1)≥0
therefore
X ≤ - 3 or X ≥ 1
The solution of equation x squared minus (3 / 2) x plus 1 / 2 greater than zero?
X squared minus (3 / 2) x plus 1 / 2 is greater than zero
2x^2 - 3x + 1 > 0
（2x - 1）（x - 1）> 0
X > 1 or x < 0.5
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