Factorization: (a + b) ^ 3 - (a + b) a^2(x-y)^2-b^2(y-x)^2 (5a^2-2b^2)^2-(2a^2-5b^2)^2 It is calculated by a simple method 57^2×0.01-43^2×0.01

Factorization: (a + b) ^ 3 - (a + b) a^2(x-y)^2-b^2(y-x)^2 (5a^2-2b^2)^2-(2a^2-5b^2)^2 It is calculated by a simple method 57^2×0.01-43^2×0.01

( a + b )"' - ( a + b )
= ( a + b )[ ( a + b )" - 1 ]
= ( a + b )[ ( a + b )" - 1" ]
= ( a + b )( a + b + 1 )( a + b - 1 )
a"( x - y )" - b"( y - x )"
= [ a( x - y ) ]" - [ b( x - y ) ]"
= [ ( ax - ay ) + ( bx - by ) ][ ( ax - ay ) - ( bx - by ) ]
= ( ax - ay + bx - by )( ax - ay - bx + by )
( 5a" - 2b" )" - ( 2a" - 5b" )"
= [ ( 5a" - 2b" ) + ( 2a" - 5b" ) ][ ( 5a" - 2b" ) - ( 2a" - 5b" ) ]
= ( 5a" - 2b" + 2a" - 5b" )( 5a" - 2b" - 2a" + 5b" )
= ( 7a" - 7b" )( 3a" + 3b" )
= 21( a" + b" )( a + b )( a - b )
57" X 0.01 - 43" X 0.01
= 5.7" - 4.3"
= ( 5.7 - 4.3 )( 5.7 + 4.3 )
= 1.4 X 10
= 14
perhaps
= 0.01 X ( 57" - 43" )
= 0.01 X ( 57 + 43 )( 57 - 43 )
= 0.01 X 100 X 14
= 14

Factorization of a-tripartite + b-tripartite + c-tripartite-3abc

a^3+b^3+c^3-3abc
=(a+b)^3-3ab(a+b)+c^3-3abc
=(a+b)^3+c^3-3ab(a+b)-3abc
=(a+b+c)^3-3(a+b)*c*(a+bc)-3ab(a+b+c)
=(a+b+c)*[(a+b+c)^2-3ab]
=(a+b+c)(a^2+b^2+c^2-ab-ac-bc)
Next, expand and merge similar items = (a-b + B-C) ^ 3 + 3 (a-b) (B-C) (a-b + B-C) + (C-A) ^ 3
=(a-c)^3+3(a-b)(b-c)(a-c)-(a-c)^3
=3(a-b)(b-c)(a-c)

Can (a + b) (a-b) be factorized~~~~~~~~~~~~~~~~~~~~~~~~~

Did you learn the radical? Did you learn the plural?
In the range of real numbers, only when a and B are not negative can we continue to decompose (we can decompose them all the time), but only in specific problems. Otherwise, what we have now is the most concise;
In the complex number range, of course, it can be decomposed, because I & sup2; = - 1, it can still be decomposed all the time, and it can only be decomposed in specific problems