The square of 2x-7x-19x + 60 has a factor 2x-5. Try to factorize the original polynomial

The square of 2x-7x-19x + 60 has a factor 2x-5. Try to factorize the original polynomial

There are 2x-5
Then the original formula = 2x & sup3; - 5x & sup2; - 2x & sup2; + 5x-24x + 60
=x²(2x-5)-x(2x-5)-12(2x-5)
=(2x-5)(x²-x-12)
=(2x-5)(x-4)(x+3)

Let f (x) = ax ^ 3 + BX ^ 2 + CX be an odd function on R, and f (1) = 3, f (2) = 12
If (A-1) ^ 3 + 2a-4 = 0 (B-1) ^ 3 + 2B = 0, find the value of a + B

My friend, I doubt the correctness of your question. As the question says, f (x) is an odd function on R, so there is f (- x) = - f (x) then B = 0, but there is a contradiction between (B-1) ^ 3 + 2B = 0 and B ≠ 0. If the equation in the question is (A-1) ^ 3 + 2a-4 = 0 * (B-1) ^ 3 + 2B = 2B = 0, then this question has nothing

Let f (x) = ax ^ 3 + BX ^ 2 + CX + d be an odd function, and if x = - radical 3 / 3, f (x) has a minimum value of - 2 radical 3 / 9
1、 If the maximum value of function g (x) = MF (x) + F '(x) on X ∈ [0,2] is 1, find the value range of real number M. 3. Let a (x1, Y1) and B (X2, Y2) be two points on f (x) image, and - 2 ＜ x1 ＜ - 1 ＜ x2 ＜ 0, point C (1,0), is the angle ACB = 90? Prove your conclusion

(1) ∵ is an odd function, so f (- x) = - ax ^ 3 + BX ^ 2-cx + D = - f (x) ∵ B = 0, d = 0 ∵ f '(x) = 3ax ^ 2 + C f' (- √ 3 / 3) = a + C = 0, f (- √ 3 / 3) = - √ 3 / 9A - √ 3 / 3C = - 2 √ 3 / 9, a = - 1, C = 1, f (x) = - x ^ 3 + X (2) g (x) = - MX ^ 3 + mx-3x ^ 2 + 1 ∵ G '(x) = - 3mx ^ 2-6x + m ∵ g (x) ≤ 1