Calculate 1 × 2 + 23 + 34 + 45 + 56 + +99100 results

Calculate 1 × 2 + 23 + 34 + 45 + 56 + +99100 results

n(n+1)=n²+n
therefore
1×2+2×3+3×4+4×5+5×6+… +99×100
=1×（1+1）+2×（2+1）+3（3+1）+...+99×（99+1）
=1²+1 + 2²+2 +3²+3 +4²+4 +...+ 99²+99
=(1²+2²+3²+4²+...+99²)+(1+2+3+...99)
1+2+3+...+99=4950
1²+2²+3²+.+99²=99（99+1）(198+1)/6=325050
Therefore, the original formula = 325050 + 4950
=330000

Calculate the result of 1 x 2 + 23 + 34 + 45 + 56 + ····· + 99100

Let x = 1x2 + 2x3 + 3x4 + 4x5 + 5x6 + ······ + 99x100
=[1x1+1]+[2x2+2]+[3x3+3]+[4x4+4]+.+[99x99+99]
=1x1+2x2+3x3+4x4+.+99x99+(1+2+3+4+.+99)
=99x(99+1)x(99+2)/6+99x(99+1)/2
=99x50x37+99x50
=99x50x38
=188100

1/12+1/23+1/34+1/45+1/56+.+1/9899+1/99100

LZ missed a multiplication sign
For the general term 1 / N * (n + 1) = 1 / n-1 / (n + 1), then replace n with 1,2,3 and. 99, and add up all the formulas to get the original formula = 99 / 100

How many digits is 2 ^ 56? How to calculate?

2^56=10^x
Take logarithm on both sides and find X
The answer is x + 1
Then x = 56lg2
lg2≈0.3
Then x = 56 * 0.3 = 16.8
Then 2 ^ 56 is 16 + 1 = 17 digits

What is the position of 6 in 56? What is the position of 6

One digit six one digit

2100 divided by a two digit number, the remainder is 56, find the two numbers

2100/73=28…… fifty-six

The number composed of five tens and six ones is (56). What is it larger than the largest single digit?

The largest single digit is 9;
56-9 = 47, 47 larger than the largest single digit
Do you mean this?

Make 34, 56, 58 and 1

The four numbers are out of proportion

How to find the least common multiple of 36,42,56

36=2*2*3*3
42=2*7*3
56=7*2*2*2
2*2*2*3*3*7=504

Decomposition factors 12 and 8 72 and 64 78 and 56 120 and 32
Find their greatest common factor.

12 and 8
12=2*2*3 8=2*2*2
The greatest common cause of 12 and 8 is 2 * 2 = 4
72 and 64
72=2*2*2*3*3
64=2*2*2*2*2*2
The greatest common cause of 72 and 64 is 2 * 2 * 2 = 8
78 and 56
78=2*3*13
56=2*2*2*7
The greatest common cause of 78 and 56 is 2
120 and 32
120=2*2*2*3*5
32=2*2*2*2*2
The greatest common cause of 120 and 32 is 2 * 2 * 2 = 8
This is the first answer. I wish you progress!