If the image of function f (x) passes through point (4,2), then the inverse function of function f (x + 1) passes through point? Why does the analysis say that when x + 1 = 4, that is, x = 3, y = 2, so the function f (x + 1) passes through (3,2). Why (3,2), what is the relationship between F (x + 1) and f (x)

If the image of function f (x) passes through point (4,2), then the inverse function of function f (x + 1) passes through point? Why does the analysis say that when x + 1 = 4, that is, x = 3, y = 2, so the function f (x + 1) passes through (3,2). Why (3,2), what is the relationship between F (x + 1) and f (x)

Note that the f (x) image passes through the point (4,2), indicating that f (4) = 2,
To make f (x + 1) adapt to f (4), we have to make x + 1 = 4,
That is, x = 3
So the function f (x + 1) passes (3,2)
The image shape of F (x + 1) is the same as that of F (x), but f (x + 1) is the result of F (x) moving one unit to the left
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Senior one compulsory four 1
If the radian ratio of one inner angle of a regular polygon to another is 144:3.1415926
Which polygons meet the conditions?

The inner angle of a positive n-polygon is (n-2) / nx180 degrees, and the radian is (n-2) / nxpi
Let the former be n-sided and the latter m-sided
(n-2)m/[(m-2)n]x180/pi=144/pi
It is reduced to: M = 8N / (10-N)
So 3=