Let a = {x | (x + 2) (x-1)

Let a = {x | (x + 2) (x-1)

From (x + 2) (x-1) 1, so a = {x | x < - 2 or x > 1},
From x + 1

Let a = {x | x greater than or equal to 1 and less than 2}, B = {x | x greater than or equal to 0 and less than a}, (a greater than 0) find a union B and a intersection B

A={x|1≤x＜2}
B={x|0<x<a}
0<a<1
AUB = {x | 0 & lt; X & lt; a or 1 ≤ x < 2}
A∩B=∅
1≤a≤2
AUB={x|0<x＜2}
A∩B={x|1≤x＜a}
a>2
      AUB={x|0<x＜a}
      A∩B={x|1≤x＜2}

Let x ~ B (2x + 1), then (2x + 1) be equal to
Yes, then d (2x + 1) is equal to.

If x ~ B (n, P), e (x) = NP
D(X)=P(1-P)
D (AX + b) = the square of a D (x)