1-ax = 6-x (where a is not equal to 1) Try to solve the equation about X: quarter 2x-a = third x-a-half

x=5/1-a

Ax plus 2 by equals 6 2cx equals 2 x equals 1 y equals - 1 find a plus B plus C

ax+2by=6 (1)
2cx=2 (2)
x=1 (3)
y=-1 (4)
Substituting x into (2), C = 1; substituting x, y into (1), 2a-b = 6
a. There are many groups of solutions to B, and the answer to a + B + C is not unique

It is known that the solution set of inequality (a + 1) x > - 2 of X is X

Yu Xue 009,
The solution of (a + 1) x > - 2 is x < 1
So a + 1 is less than 0
Then divide both sides by a + 1
x＜-2/（a+1）
-2/（a+1）=1
a+1=-2
a=-3

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