X (x + 1) = 5x (X-2) by factorization, thank you

X (x + 1) = 5x (X-2) by factorization, thank you


x(x+1)=5x(x-2)
x²+x = 5x² -10x
11x = 4x²
X = 0 or x = 11 / 4



Given that 2x ^ 3 + x ^ 2 + KX + 2 can be divisible by 2x + 1 / 2, find K "


A:
Let Q be a polynomial such that: (2x + 1 / 2) q = 2x ^ 3 + x ^ 2 + KX + 2
Let f (x) = 2x ^ 3 + x ^ 2 + KX + 2, when 2x + 1 / 2 = 0, that is, x = - 1 / 4, f (x) = (2x + 1 / 2) q = 0
f(-1/4)=-1/32+1/16-k/4+2=0
The solution is k = 65 / 8
So k = 65 / 8