If 2x ^ 2-kx ^ 3 + 3 is divisible by 2x + 1, the remaining 2 is obtained

If 2x ^ 2-kx ^ 3 + 3 is divisible by 2x + 1, the remaining 2 is obtained

That is to say, the polynomial formula can be written as (2x + 1) (AX & sup2; + BX + C) + 2, so we substitute x = - 1 / 2 into x = - 1 / 2
2(-1/2)²-k(-1/2)³+3=2
That is, K / 8 = - 3 / 2
K = - 12

The cube of 2x - the square of X - 13X + K. after factorization, there is a factor of 2x + 1. To find the value of K, we need to take detailed steps

The cube of 2x - the square of X - 13X + K. after factorization, there is a factor of 2x + 1
A solution equivalent to the equation [cube of 2x - square of X - 13X + k = 0] is the solution of [2x + 1 = 0], that is, x = - 1 / 2
Substitute x = - 1 / 2 into the cube of 2x - 13X + k = 0
2*(-1/8)-1/4-13*(-1/2)+k=0
k=-6

When x = - 2, the value of the algebraic expression ax & # 179; + bx-7 is 9, then when x = 2, ax & # 179; + bx-7 =?