1. Let a = {x2-3x + 2 = 0} and B = {x AX-2 = 0}. If B is a proper subset of a, it is a set of A 2. Let m = {(x, y) ｜ x-a = 4}, and {(2,1), (- 2,5)} be the proper subset of M, then a=____ b=_____ 3. A = {x 2 + X + P = 0}, B = {x ≥ 0, X ∈ r}, a ∩ B = empty set, find the value range of real number P 4. Let a = {x 2 4x = 0}, B = {x 2 + 2 (a + 1) x + a 2-1 = 0, X ∈ r} (1) If a ∩ B = B, find the value of A (2) If a ∪ B = B, find the value of A 5. Let a = {x 2 + ax + B = 0}, B = {x 2 + CX + 15 = 0}, and a ∪ B = {3,5}, a ∩ B = 3, find the value of real numbers a, B, C

1. Let a = {x2-3x + 2 = 0} and B = {x AX-2 = 0}. If B is a proper subset of a, it is a set of A 2. Let m = {(x, y) ｜ x-a = 4}, and {(2,1), (- 2,5)} be the proper subset of M, then a=____ b=_____ 3. A = {x 2 + X + P = 0}, B = {x ≥ 0, X ∈ r}, a ∩ B = empty set, find the value range of real number P 4. Let a = {x 2 4x = 0}, B = {x 2 + 2 (a + 1) x + a 2-1 = 0, X ∈ r} (1) If a ∩ B = B, find the value of A (2) If a ∪ B = B, find the value of A 5. Let a = {x 2 + ax + B = 0}, B = {x 2 + CX + 15 = 0}, and a ∪ B = {3,5}, a ∩ B = 3, find the value of real numbers a, B, C

1. Let a = {x2-3x + 2 = 0} and B = {x AX-2 = 0}. If B is a proper subset of a, it is a set of A
A=｛1,2｝
B is the proper subset of A
B = {1} or {2}
A = 2 or 1
So it is a set of a = {1,2}
2. Let m = {(x, y) ｜ x-a = 4}, and {(2,1), (- 2,5)} be the proper subset of M, then a=____ b=_____ [problem]
3. A = {x 2 + X + P = 0}, B = {x ≥ 0, X ∈ r}, a ∩ B = empty set, find the value range of real number P
B = {x ≥ 0, X ∈ r}, a ∩ B = empty set
x1x2=c/a=p>0
4. Let a = {x 2 4x = 0}, B = {x 2 + 2 (a + 1) x + a 2-1 = 0, X ∈ r}
(1) If a ∩ B = B, find the value of A
A=｛x2｜4x=0｝={0}
A∩B=B
B = empty set
Discriminant

If f (x) is an even function, G (x) is an odd function, and f (x) + G (x) = x2 + X-2, find the analytic expressions of F (x) and G (x)

∵ f (x) is an even function, ∵ f (- x) = f (x), ∵ g (x) is an odd function, ∵ g (- x) = - G (x), ∵ f (x) + G (x) = x2 + X-2 ∵ f (- x) + G (- x) = x2-x-2, i.e. f (x) - G (x) = x2-x-2 & nbsp; 2. The solution is: F (x) = x2-2, G (x) = X

Given that f (x) is an odd function, G (x) is an even function, and f (x) + G (x) = 1 / (2x + 1), find the analytic expressions of F (x), G (x)

f(-x)=-f(x)
g(-x)=g(x)
Let H (x) = f (x) + G (x) = 1 / (2x + 1)
So h (- x) = - f (x) + G (x) = 1 / (- 2x + 1),
Add
2g(x)=1/(2x+1)+1/(-2x+1)=2/(1-4x²)
g(x)=1/(1-4x²)
f(x)=h(x)-g(x)=-2x/(1-4x²)