For the function y = f (x) defined on the set D, if f (x) has monotonicity on D and has interval [a, b] ⊆ D, so that when x ∈ [a, b], the range of F (x) is [a, b], then the function f (x) is said to be a positive function on D, and the interval [a, b] is called the "equal domain interval" of F (x). Given that the function f (x) = x is a positive function on [0, + ∞), then the equal domain interval of F (x) is___ ．

For the function y = f (x) defined on the set D, if f (x) has monotonicity on D and has interval [a, b] ⊆ D, so that when x ∈ [a, b], the range of F (x) is [a, b], then the function f (x) is said to be a positive function on D, and the interval [a, b] is called the "equal domain interval" of F (x). Given that the function f (x) = x is a positive function on [0, + ∞), then the equal domain interval of F (x) is___ ．

Because f (x) = x is an increasing function on [0, + ∞), when x ∈ [a, b], the range of F (x) is [f (a), f (b)], and f (x) = x is a positive function on [0, + ∞), the solution is a = 0, B = 1, the isodomain interval of F (x) is [0, 1]. So the answer is: [0, 1]

For functions f (x) and G (x) defined on interval D
For functions f (x) and G (x) defined on interval D, if for any x, | f (x) - G (x) / F (x)|

Hypothesis exists
|f(x)-g(x)/f(x)|

If the function f (x) is an increasing function on an interval I in the domain D, and f (x) = f (x) / X is a decreasing function on I, then
Please see the question within an hour to solve 100 points!

If h (x) = x & # 178; - (B-1) x + B is a weakly increasing function on (0,1], then:
(1) Let (b) be an increasing function of (x-1) / 0
(2) If G (x) = H (x) / x = x + (B / x) + (B-1) decreases on (0,1), then: √ B ≥ 1, then: B ≥ 1
Thus, B = 1