The function of the following program is to calculate the number of different ways of 3 digits composed of any 3 different numbers from 0 to 9 main( ) { int i,j,k,count=0; for(i=9; i>=1; i--) for(j=9; j>=0; j--) if(______ ) continue; else for(k=0; k

The function of the following program is to calculate the number of different ways of 3 digits composed of any 3 different numbers from 0 to 9 main( ) { int i,j,k,count=0; for(i=9; i>=1; i--) for(j=9; j>=0; j--) if(______ ) continue; else for(k=0; k

I is a hundred (because I is not equal to zero), j is ten, and K is one
The first if (I = = J) guarantees that the two digits are not equal
The second if (k! = I & & K! = J)
It's like this
This is where the problem, ah, with triple circulation can not be

Write a 4-digit number which is not the same. Use the 4-digit number in this book together with its symbol to form the maximum and minimum number respectively, and calculate the difference, 6174
Write an arbitrary 4-digit number with different numbers. Use the 4-digit number in this book together with its symbol to form the maximum and minimum number respectively, and calculate the difference. Then repeat the above operation for the difference. What's the result?
I used the program to find that the final number will always loop in 6174
But why? Proof
Is there a proof for this problem?
6174 = 7 * 7 * 7 * 3 * 3 * 2 is there anything special about it?
What happens if you change to 3-digit, 5-digit and 6-digit?

Any four digit number that is not made up of exactly the same number, if each digit of them is reordered to form a larger number and a smaller number, and then the smaller number is subtracted from the larger number, and if the difference is less than four digits, zero will be filled, and so on, and finally it will become a fixed number: 6174, which is the kabulek constant

Write a three digit number that is different from each other. Use the three digits to form a maximum three digit number and a minimum three digit number
And subtract the minimum number from the maximum number to get a new number. For the new three digits, repeat the above process to get a new number. Then continue as above. What do you find?

In the end, it's 954-459 = 495

Calculation: X & # 178; (x-1) - 2x (X & # 178; - 2x + 3)

x²（x-1）-2x（x²-2x+3）
=x³-x²-2x³+4x²-6x
=-x³+3x²-6x
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If the square of 1 / 3x - 2Y + 6 = 10, then the square of X - 6y=____________ .

The square of 1 / 3x - 2Y + 6 = 10,
Then the square of 1 / 3x - 2Y = 4
x²-6y=12

（2y-1)²+3=6y

（2y-1)²+3=6y
4y^2+1-4y+3-6y=0
4y^2+4-10y=0
2y^2+2-5y=0
(y-2)(2y-1)=0
Y = 2 or y = 1 / 2

If 13x2 − 2Y + 6 = 10, then x2-6y=______ ．

∵ 13x2 − 2Y + 6 = 10, ∵ x2-6y + 18 = 30, ∵ x2-6y = 12

What number's derivative is equal to 1 / (1 + x)

That is to find indefinite integral for 1 / (1 + x)
The derivative of y = ln | x + 1 | + C is equal to 1 / (1 + x) and C is any constant

What is the derivative of (1 + X squared) e squared-1?

y=e^2(1+x^2)-1
=e^2x^2+e^2-1
So:
y'=2xe^2.

What number's derivative is equal to 1 / X (x + 1)
I can't solve this problem

1/x(x+1)=1/x-1/（x+1）
The integral is lnx-ln (x + 1) = ln | X / (x + 1) | + C
The derivative of is equal to 1 / X (x + 1)