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Among the integers no more than 1000, there is a number whose square root is an integer and cube root is not an integer. What are the differences?

4 9 16 25 36 49 81 100 121 144 169 196 225 256 289 324 361 400 441 484 529 576 625 676 784 841 900 961

(X-Y) x - (x + y) y + (x to the second power - y to the second power) 2XY

(X-Y) of X - (x + y) of Y + (x to the 2nd power of - y) of 2XY = (X-Y) of X - (x + y) of Y + (X-Y) (x + y) of 2XY = (X-Y) (x + y) of [x (x + y) - Y (X-Y) + 2XY] = (X-Y) (x + y) of (x square + 2XY + y Square) = (X-Y) (x + y) of (x + y) of (x + y) = (x + y) of (X-Y) = (x + y) of (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (

X quadratic y (X-Y) quadratic - 2XY (Y-X) quadratic
Factorization

The original formula = x & # 178; Y (X-Y) & # 178; - 2XY (X-Y) & # 178;
=xy(x-y)²(x-2)

What number has a derivative equal to 1 / x

lnlxl+c

The second power X of (- 5) / (- 3 △ 5) / (- 9 △ 25)=
fast

The second power X of (- 5) / (- 3 △ 5) / (- 9 △ 25)
=25×（-3/5）×（-25/9）
=125/3
=41 and 2 / 3

What is the product of 10 to the 12th power × 5

A 5 followed by 12 zeros is 500000000000, or directly write 5 times 10 to the 12th power

The 12th power of 5.81 * 10 - the 10th power of 5 * 10 / (- the 4th power of 1.25 * 10) * (the 6th power of 1.6 * 10) (the results were expressed by scientific counting method)

(12th power of 5.81 * 10-10th power of 5 * 10) / (- 4th power of 1.25 * 10) * (6th power of 1.6 * 10)
=5.76 * 10 to the 12th power / (- 2 * 10 to the 10th power)
=-The second power of 2.88 * 10

3.8 square decimeter = () square meter

1 square meter = 100 square decimeter 3.8 square decimeter = 3.8 / 100 = 0.038 square meter

1 square meter 8 square decimeter = how many square meters?

1 square meter 8 square decimeter = fraction of a few square meters
One and two quarters

Input the square root of an integer less than 1000 from the keyboard After inputting data, check whether it is a positive number less than 1000. If not, re input is required #include #include int main() { int x,y; Printf ("enter an integer less than 1000"); scanf("%d",&x); if(x>=1000&&x