It is known that the solutions of the equations 2x + 5Y = - 6 ax by = - 4 and 3x-5y = 16 BX = ay = - 8 are the same Known equations 2x + 5Y = - 6 Ax by = - 4 and the equations 3x-5y = 16 BX=AY=-8 Find the value of (2a + b) 2007 with the same solution If I3A + B + 5L + l2a-2b-2l = 0, what is the square of 2a-3b = If the system of equations x+Y+2a If the solution of X-Y = 4A is a solution of 3x-5y-28 = 0, then a = () A1 or - 1 B 2 C 7 d 6 In the square + ax + B of the algebraic formula x, when x = 2, its value is 3, when x = - 2, its value is 19. Then the value of the algebraic formula A-B is () A -11 B11 C 3 D-3 Well, it's BX + ay = - 8

It is known that the solutions of the equations 2x + 5Y = - 6 ax by = - 4 and 3x-5y = 16 BX = ay = - 8 are the same Known equations 2x + 5Y = - 6 Ax by = - 4 and the equations 3x-5y = 16 BX=AY=-8 Find the value of (2a + b) 2007 with the same solution If I3A + B + 5L + l2a-2b-2l = 0, what is the square of 2a-3b = If the system of equations x+Y+2a If the solution of X-Y = 4A is a solution of 3x-5y-28 = 0, then a = () A1 or - 1 B 2 C 7 d 6 In the square + ax + B of the algebraic formula x, when x = 2, its value is 3, when x = - 2, its value is 19. Then the value of the algebraic formula A-B is () A -11 B11 C 3 D-3 Well, it's BX + ay = - 8

Because the solution is the same, simultaneous 2x + 5Y = - 6, 3x-5y = 16, the solution is x = 2Y = - 2, substituting x = 2 into ax by = - 4bx + ay = - 8, the solution is b = - 3A = 12a + B = 2-3 = - 1 (2a + B) ^ 2007 = - 1. Because the absolute value of a number must be greater than or equal to 0, 3A + B + 5 = 02a-2b-2 = 0, the solution is a = - 1B = - 22a & sup2; - 3B = 2

Given that the solutions of the equations 2x + 5Y = - 6 and ax by = - 4 and 3x-5y = 16 and BX = ay = - 8 about X and y are the same, find (2a + b)
Find the value of (2a + b) to the power of 2010.

By combining 2x + 5Y = - 6 and 3x-5y = 16, we get that X and y are 2 and - 2 respectively, and ax by = - 4 and BX = ay = - 8, we get that a and B are - 3 and 1 respectively, and the power of (2a + b) equal to - 1 is equal to 1

Given that the solutions of the equations 2x + 5Y = - 6, ax by = - 4 are the same as those of the equations 3x-5y = 16, BX + ay = - 8, find the square of (a + b)

We can solve 2x + 5Y = - 6 first
3x-5y=16
Add
5x=10
x=2,y=(-6-2x)/5=-2
Substituting ax by = - 4
2a+2b=-4
a+b=-2
(a+b)^2=4

Given that the solution of the system of equations (AX + by = 4) (BX + ay = 5) satisfies x + y = 3, what is a + B

You may have the wrong number at the beginning
ax+by=4
bx+ay=5
Add the above two equations to get
ax+bx+by+ay=9
(a+b)x+(a+b)y=9
(a+b)(x+y)=9
3(a+b)=9
So a + B = 3