Given that x = 3 is the solution of equation 3 [(X3 + 1) + m (x − 1) 4] = 2, n satisfies the relation | 2n + m | = 1, the value of M + n is obtained
Substituting x = 3 into the equation 3 [(X3 + 1) + m (x − 1) 4] = 2, we get 3 (2 + m2) = 2, and the solution is m = - 83. Substituting M = - 83 into | 2n + m | = 1, we get | 2n-83 | = 1, and we get: ① 2n-83 = 1, ② 2n-83 = - 1. Solving ①, n = 116, and solving ②, n = 56
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