Given that x = 3 is the solution of the equation (x + 3) △ 3 + m (x-1) = 3, m and N satisfy the relation / 2n + m / = 4010, try to find the value of M + n

Given that x = 3 is the solution of the equation (x + 3) △ 3 + m (x-1) = 3, m and N satisfy the relation / 2n + m / = 4010, try to find the value of M + n

(X+3)÷3 +m(x-1)=3
2 m + 2 = 3
M=1/2
/2n+m/=4010
Then 2n + 1 / 2 = 4010
N=2004.75
M+N=2005.25
Or 2n + 1 / 2 = - 4010
N=-2005.25
M+N=-2005.25+0.5=-2004.75

Given that x = 3 is the solution of the equation x + 3 / 3 + m (x-1) = 3, m and N satisfy the relation | 2n + m | = 4010, then M + n =?

x=3
Then (3 + 3) / 3 + m (3-1) = 3
2+2m=3
m=1/2
|2n+m|=4010
2n+m=±4010
2n=-8021/2,2n=8019/2
n=-8021/4,n=8019/4
So m + n = - 8019 / 4, M + n = 8021 / 4

It is known that {x = 3, y = 1} and {x = - 1, y = - 3 / 5} are two solutions of the quadratic equation AX + by = 3 with respect to X and Y (1) finding the values of a and B: (2) when x = 5,
Y = - 1 is to find the value of the algebraic expression ax + by

X = 3, y = 1 the solution of the quadratic equation AX + by = 3 with respect to x, y
∴3a+b=3……………… ①
X = - 1, y = - 5 also on the solution of the quadratic equation AX + by = 3
∴-a-5b=3……………… er5
By solving the system of equations formed by (1) and (2), it is concluded that
a=9/7 b=-6/7