Extremum of binary function What is the value of F (x, y) x ^ 2 + 2Y ^ 2-lnx-lny in the domain

Extremum of binary function What is the value of F (x, y) x ^ 2 + 2Y ^ 2-lnx-lny in the domain


∵ f'x = 2x-1 / x = (2x & sup2; - 1) / x, f'y = 4y-1 / y = (4Y & sup2; - 1) / y. let f'x = 0, we get x = ± 1 / √ 2. Let f'y = 0, we get y = ± 1 / 2 ∵ we get four stable points: (1 / √ 2,1 / 2), (1 / √ 2, - 1 / 2), (- 1 / √ 2,1 / 2), (- 1 / √ 2, - 1 / 2) ∵ a = f '' - x =



What is the extremum of binary function
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This should be the concept of derivative. When the derivative of a binary function is 0, the point corresponding to the value of X is the extreme point, and the corresponding y is the extreme value (with maximum and minimum). For example, a y = x ^ 2 + X. if the derivative is y '= 2X + 1 = 0 and x = - 1 / 2, the minimum is - 1 / 4
The lowest point is the minimum value, otherwise it is the maximum value