If we know that the | m | - 1 power of (m-2) times x = 1, we can solve the linear equation of one variable

If we know that the | m | - 1 power of (m-2) times x = 1, we can solve the linear equation of one variable

Because it's a linear equation of one variable
So m - 2 ≠ 0 and | m | - 1 = 1
m - 2 ≠ 0
m ≠ 2
|m| - 1 = 1
|m| = 2
M = 2 or M = - 2
To sum up, M = - 2

There are eight boxes, each of which contains the same kind of pen. The number of pens in the eight boxes are 17, 23, 33, 36, 38, 42, 49 and 51 respectively. Among these pens, the number of ballpoint pens is twice that of pens, and the number of pens is 13 times that of pencils. There is only one watercolor pen in the box______ One branch

If the pen is 1, then the ballpoint pen is 2 and the pencil is 3. The total number of these three pens must be a multiple of 6, that is, they can be divided by 2 and 3 at the same time. Because the number of pens in 3 of the 8 boxes is even, and the number of pens in 5 boxes is odd, according to even + odd = odd, it can be seen that there must be 3 pens in 7 boxes containing pencils, ballpoint pens and pens Even number of pens, 4 boxes with odd number of pens, the box with watercolor pens must have odd number of pens. Add up the number of pens in 8 boxes: 1 + 7 + 2 + 3 + 3 + 3 + 3 + 6 + 3 + 8 + 4 + 2 + 4 + 9 + 5 + 1 = 64; because 64 - (4 + 9) = 51 can be exactly divided by 3, the box with watercolor pens has 49 pens

Equation or formula
Now the number of boys in the class is 5 / 4, and the number of girls in the class is 5 / 6?

Suppose the number of boys is X
If the number of boys remains the same, the equation is as follows:
4/5X+1 = 5/6X
Solve the equation and get x = 30
Now there are 55 students in the class