How to solve the equation of 5x + 6x-9 = 13

How to solve the equation of 5x + 6x-9 = 13

(5+6)x=9+13
11x=22
x=22/11
x=2

How to solve 9x ^ 2 + 6x + 1 = 0 by formula method

The formula of ax BX C = 0 is: x = [- B ± √ (B - 4ac)] / 2A 1) x X-1 = 0 (substituting a = 1, B = 1, C = - 1 into the above formula respectively) x = [(- 1) ± √ (1, 4)] / 2x1=

How to solve 9x square plus 6x plus 1 = 0 by formula method?

This simple formula is equivalent to (3x + 1) = 0, and the formula method is x = [- B ± root (b-4ac)] / 2A = - 6 / 2x9 = - 1 / 3

How to solve the formula of 9x square + 6x + 1 = 0

a=9,b=6,c=1
△=b²-4ac=36-36=0
So x = (- 6 ± 0) / (2 × 9)
x=-1/3

Use formula method to find 9x square 6x 1 = 0, whatever you set!

（3x-1）^2=0
3X-1=0
X=1/3
I hope I can help you,

How to use factorization (3x-5) (2x-1) = - 12x + 7

(3x-5)(2x-1)=-12x+7
6x＾2-13x+5=-12x+7
6x＾2-x-2=0
(2x+1)(3x-2)=0
X = - 1 / 2 or 2 / 3

2X (X-5) = 15-3x factorization

2x(x-5)+3x-15=0
2x(x-5)+3(x-5)=0
(x-5)(2x+3)=0
x=5,x=-3/2

The method of general division, 1 / x + 1 / 3x + 2 = 1 / 8

1/X+1/3X+2=1/8
1/x+1/(3x+2)=1/8
[3x+2+x]/(3x+2)=1/8
[3x+2+x]/(3x+2)-1/8=0
[8(4x+2)-(3x+2)]/8(3x+2)=0
(29x+14)/8(3x+2)=0
So 29x + 14 = 0
X = - 14 / 29

Solve the equation [3x-11] [X-2] = 0

(3x-11)(x-2)=0 x1=11/3 x2=2

Solution equation: (x + 4) (3x-2) + 11 = 0 (by formula method)

Solution
(x+4)(3x-2)+11=0
Namely
3x²+10x+3=0
Formula method
x=(-10+√100-36)/6=(-10+8)/6=-1/3
x=(-10-√100-36)/6=(-10-8)/6=-3