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The quotient of the number a divided by the number B is 15, the remainder is 10, the sum of the number a and the number B is 330, and the number a is 1______ The number B is______ ．
Let B be x, then a is 15x + 10, x + 15x + 10 = 330 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 16x = 320 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 20 × 15 + 10 = 310 A: A is 310, B is 20, so the answer is 310, 20
The sum of a and B is 470, the quotient of a divided by B is 8, the remainder is 2, what is B?
52
Finding two roots of equation 3x ^ 2-5x-2 = 0
3x^2-5x-2=0
(3x+1)(x-2)=0
X = - 1 / 3 or x = 2
3x what = 28 makes the solution of the equation x = 8
3x+4 = 28
The solution of the equation is x = 8
When 3 〈 a 〈 8, the solution of the equation 3x-8 = a (x-1) about X is ()
fast
A. B positive number C zero D negative number
D
X = 8 is the solution of the equation 3x-3 = x / 42a and X-1 / 3 [X-1 / 3 (X-B)]=
=1 / 9 [x + b], B
3X-3=X/4 2a X-1/3［X-1/3（x-b）］=1/9［X+b］
3*8-3=8/42a 8-1/3［8-1/3（8-b）］=1/9［8+b］
a=441/4 b=24
If x = 3, y = - 1 is the solution of the equation 3x by = 8, then B = what
Substitute X and Y into the formula
9+b=8
b=-1
(1) How to solve the two equations of - 3-3x + 5 = - 8 (2) 3x + 4 = x?
1.-3x=-8-5+3
-3x=-10
x=10/3
2.3x-x=-4
2x=4
x=2
There is an equation problem in Xiaoqiang's exercise book. One of the numbers is polluted by ink and becomes a problem
1 / 3 (negative half of X-1 + x) = 1-fifth of X - △ where △ is the polluted number. He turned the answer after the book and knew that the solution of the equation was x = 5. So he solved the polluted number and wrote out the calculation process of Xiaoqiang
1 / 3 (negative half X-1 + x) = 1-fifth X - △ the solution is x = 5
Then 1 / 3 (- 4 / 2 + 5) = 1-5 (5 - △)
1 / 3 * (- 2 + 5) = 1-5 (5 - △)
1 = 1-5 (5 - △)
(5 - △ of 5) = 0
5-△=0
△=5
When Xiao Ming was doing his homework, there was an equation problem in his exercise book. One of the numbers was polluted by ink and became (x + 1 / 2 - (5x - ·) / 3. The solution of the equation was 2
If we take x into the equation, we get the following result:
2+1/2-5×2-（）/3=-1/2
2/5-10+1/2=（）/3
3-10=（）/3
-7=（）/3
（）=-21
RELATED INFORMATIONS
- 1. If the divisor, divisor, sum of quotient and remainder is 143, the divisor is larger than the divisor______ ．
- 2. The sum of the divisor quotient and the remainder is 143. The divisor is () and the divisor is () emergency
- 3. The sum of the quotient and the remainder is 143. What is the divisor?
- 4. The quotient of dividing two numbers is 9, and the remainder is 8. What is the largest divisor? What is the divisor?
- 5. Find the remainder of the product 288 times 226 times 423 divided by 13!
- 6. If the number a is divided by 9, the quotient 12 is more than 7; if the number B is divided by 9, the quotient 28 is more than 6; if the number C is divided by 9, the quotient 3 is more than 5?
- 7. A number divided by 4 has a remainder. What is the maximum remainder? What is the minimum remainder? Why?
- 8. If the image of exponential function f (x) = a ^ x (a > 0, a is not equal to 1) passes through points (2,9), then f (x) =?
- 9. Find (4a ^ 2 / 3B ^ - 1 / 3) divided by (- 2 / 3A ^ - 1 / 3B ^ 1 / 3)
- 10. If the power function y = f (x) is known to pass through a point (1 / 2,8), then f (- 3)
- 11. If the number a is divided by the number B, the quotient is 3 and the remainder is 5, then the sum of the two numbers is 85. What is the number a and B?
- 12. If both the divisor and the divisor are multiplied by 5, the quotient () and the remainder are ()
- 13. If the number of a is divided by the number of B, the quotient 4 is more than 5. If the number of a is increased to 4 times of the original number and the number of B remains unchanged, then the quotient 18 has no remainder?
- 14. The quotient of number a divided by number B is 14, the remainder is 2, the sum of number a, number B, quotient and remainder is 63, what's number B? We don't need to use the method of setting x ` y The child is still young
- 15. If the number a is divided by the number B, the quotient 4 is more than 5. If the number a is increased by 4 times, the number B remains unchanged. Then the quotient 18 has no remainder. The original number a is ()
- 16. If two equations x2 + ax + B = 0 and X2 + BX + a = 0 have a unique common solution, then a + B =?
- 17. Remove the negative bracket (- x + 2-x) - 1 first
- 18. Given a = 2x ^ 2-3x-1, B = 3x ^ 2 + 2X-4, when x = - 12 / 13, find the value of 3a-2b
- 19. 3x (x-1) = 2 (x-1)
- 20. How to solve the equation of 5x + 6x-9 = 13