The sum of the quotient and the remainder is 143. What is the divisor?

The sum of the quotient and the remainder is 143. What is the divisor?

Divisor (143-3-10-10) / (3 + 1) = 120 △ 4 = 30, divisor 30 × 3 + 10 = 100

There are two numbers of a and B. the number of a is divided by the number quotient of B, which is more than 7, the number of B is 10 times, and the number of a is divided by the number quotient of a, which is more than 45?

Let a be x and B be y
〔x－7〕÷y＝2 ①
〔10y－45〕÷x＝3 ②
The simplified equations are as follows
x－2y＝7 ③
－3x+10y =45 ④
③ 5
5x－10y =35⑤
④ (5) the results are as follows
2x=80
x＝40
Substituting x = 40 into (3) yields:
40－2y＝7
∴x＝40
y＝16.5
The number a is 40 and the number B is 16.5

9 times 2 + 1.5 divided by 2 minus x = x equation, to be detailed, there are points

9×2+1.5÷2-x=x
18 + 0.75 = 2x (transfer)
18.75=2x
x=18.75÷2
x=9.375

How to solve the equation of (x + 2) (x + 2) - x * x = 36

Using the law of multiplicative distribution, after expansion, we get: X * x + 4x + 4-x * x = 36
That is: 4x = 32, the solution is: x = 8

The sum of two times of 36 and X is 108

36*2+x=108
72+x=108
x=36

75% x = 60% + 15 equation

75%x =60% +15
0.75 x =0.6 +15
x = 20.8

1.25 of 0.75 = 2 of X

1.25 of 0.75 = 2 of X
1.25x=2*0.75
x=1.5/1.25
x=1.2
Note: * is multiplication sign / division sign

How to solve x △ 20-2.75 = 1.25

x/20=1.25+2.75
x/20=4
x =80

How to solve 10x (x + 16) △ 2 = 120

10x+160=240
x+16=24
x=24-16
x=8

How to solve 80 (1-5%) + 120 (1 + x) = 200 (1 + 16%)

80(1-5%)+120(1+X)=200(1+16%)
2(1-5%)+3(1+X)=5(1+16%)
1.9+3+3x=5.8
3x=0.9
x=0.3