If both the divisor and the divisor are multiplied by 5, the quotient () and the remainder are ()

If both the divisor and the divisor are multiplied by 5, the quotient () and the remainder are ()

If the divisor and the divisor are both multiplied by 5, the quotient (3) and the remainder (5)

The number a is divided by the number B, the quotient is 12 and the remainder is 3. The sum of the number a, the number B, the quotient and the remainder is 187, and what is the divisor

1. Number a + number B + 12 + 3 = 1872, sum of number a and number B: 187-12-3 = 1723, number a ／ number b = 12 3. If 3 is subtracted from 172, the number of a is 12 times of that of B, the number of B is 1, the number of a is 12, the number of a is 12, and the number of a and B is (1 + 12) in total, which is exactly (172-3)

The sum of number a and number B is 2009. The number a is divided by the number B quotient of 333. What is the number a and number B?

Number B: (2009-5) / (333 + 1) = 6
Number A: 2009-6 = 2003

How to calculate 1 = 1 / 3x + X?

1=1/3X+X
1=4/3X
X=1÷4/3
X=3/4

On the equation x / 5-2a = (1-3x) / 4 and (6-x) / 2 - (2x + 5) / 3 = 0 of X

2a=5-15x/5 a=5/2-3x
(6-x) / 2 - (2x + 5) / 3 = 0 3-5 / 2x-10 = 0 x = - 14 / 5 substituting 2A = 5-15x / 5 a = 5 / 2-3x a = 109 / 10

The solution of equation 3x-6 = 12 is 6, right? Why?

Yes
3x-6=12
3x=18
x=6

X ^ 3-6x ^ 2-3x + 10 = 0 solution

x^3-6x^2+3x+10=0
x^2(x+1)-7x(x+1)+10(x+1)=0
（x+1）（x^2-7x+10）=0
(x+1)(x-2)(x-5)=0
x1=-1 x2=2 x3=5

X + 3x + 5-1 = 24

5

Solution equation: 3 (x + 1) (x-1) - 3 (3x-1) ^ 2-10 = 10

Solution
3(x+1)(x-1)-3(3x-1)²-10=10
3(x²-1)-3(9x²-6x+1)-20=0
(3x²-27x²)+18x-3-3-20=0
-24x²+18x-26=0
12x²-9x+13=0
△=b²-4ac=81-4×12×13

X + 2Y = 10 - 3x + 5Y = 3

The solution from (1) is x = 10-2y (3)
Substituting (3) into (2) yields - 3 (10-2y) + 5Y = 3
-30+6Y+5Y=3
11Y=33
Y=3
Substituting y = 3 into (3)
X=10-2×3=4
So x = 4, y = 3