The distance between a and B is 162 kilometers. A slow train leaves from a station and walks 48 kilometers per hour. An express train leaves from B station and walks 60 kilometers per hour The two trains are going towards each other at the same time (the express train is behind). Can the express train catch up with the local train in a few hours? The two cars are facing each other at the same time (the local train is at the back). After a few hours, the two cars are 200 km apart?

The distance between a and B is 162 kilometers. A slow train leaves from a station and walks 48 kilometers per hour. An express train leaves from B station and walks 60 kilometers per hour The two trains are going towards each other at the same time (the express train is behind). Can the express train catch up with the local train in a few hours? The two cars are facing each other at the same time (the local train is at the back). After a few hours, the two cars are 200 km apart?

The equation is as follows
1) 60X=48X+162
X = 13.5 hours
2) 60X=48X+(200-162)
X = 3 and 1 / 6 hours = 3 hours and 10 minutes

There is a distance of 162 km between a and B. a slow train leaves from station a and travels 48 km per hour, while an express train leaves from station B and travels 60 km per hour
K two trains go in the same direction at the same time (the express train is behind), the express train will drive for one hour first, and then the express train can catch up with the local train in a few hours?

Suppose the fast train can catch up with the slow train in X hours
60﹙X+1﹚-48X=162
60X+60-48X=162
12X=102
X=8.5
A: in another x hours, the express can catch up with the local

The distance between station a and station B is 162 kilometers. A slow train departs from station a and travels 48 rows of meters per hour. An express train is developed from station B and travels 60 kilometers per hour

The distance between station a and station B is 162 kilometers. A slow train departs from station a and travels 48 rows of meters per hour. An express train develops from station B and travels 60 kilometers per hour. If the two trains go in the same direction at the same time (the express is behind), how many hours later can the express catch up with the slow train?
Solving linear equation with one variable
After setting x hours, the fast train can catch up with the slow train
（60-48）X=162
12X=162
X=162÷12
X=13.5
A: after 13.5 hours, the express can catch up with the local