On the Inner Mongolia prairie, there are a group of herdsmen driving a group of cattle and sheep, people and cattle. There are 27 sheep and 100 legs at the same time. How to calculate the number of people, cattle and sheep

On the Inner Mongolia prairie, there are a group of herdsmen driving a group of cattle and sheep, people and cattle. There are 27 sheep and 100 legs at the same time. How to calculate the number of people, cattle and sheep


In fact, this topic is based on the problem of "chicken and rabbit in the same cage". Analysis: given that the number of legs of human, sheep and cattle are 2, 4 and 4 respectively. It can be seen that the number of legs of human is 1 / 2 of that of cattle and sheep. With X people, it can be seen that there are 2x legs of human. Then there are {27-x} × 4 legs of cattle and sheep



The scales of maps a, B and C are 1:25000003000000 / 1 and 0-20-40-60km respectively. Which 6 cm line segment on the map represents the longest distance?
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Formula or equation or reason, shrimp can, as long as it is right, the table only write an answer==+


A 6 cm line segment represents 6 * 2500000 / 100 / 1000 = 150 km
B 6 cm line segment means 6 * 3000000 / 100 / 1000 = 180km
C 6 cm line segment means 20 * 6 = 120 km
The actual distance indicated by B is the longest



Sixth grade mathematics wide angle urgent!
There are 30 big and small steel balls in the box, weighing 266g. It is known that each big steel ball is 11g, and each small steel ball is 7g. How many big steel balls and small steel balls are there in the box?
thank you
Please write the process!!! thank you!


Set X large steel balls and 30-x small steel balls
11x+7(30-x)=266
x=14
There are 14 big balls and 16 small balls