Wide angle mathematical problems in sixth grade mathematics 1. For any seven different natural numbers, the difference between at least two of them is a multiple of 6. Why? 2. In 1,2,3,..., 49,50, at least how many different numbers must be taken out to ensure that one of them can be divided by 5? 3. There are 63 students in a class. They all participate in extracurricular interest groups. The activities include mathematics, art, calligraphy and English. Each student can participate in one, two, three or four interest groups. How many students in the class participate in the same project? 4. Give 400 cards to several students, each of whom can get no more than 11 cards. Try to prove that at least 7 students get the same number of cards How many questions can I answer? I'm in a hurry. I'm in a hurry. I'm in a hurry. I'm in a hurry

Wide angle mathematical problems in sixth grade mathematics 1. For any seven different natural numbers, the difference between at least two of them is a multiple of 6. Why? 2. In 1,2,3,..., 49,50, at least how many different numbers must be taken out to ensure that one of them can be divided by 5? 3. There are 63 students in a class. They all participate in extracurricular interest groups. The activities include mathematics, art, calligraphy and English. Each student can participate in one, two, three or four interest groups. How many students in the class participate in the same project? 4. Give 400 cards to several students, each of whom can get no more than 11 cards. Try to prove that at least 7 students get the same number of cards How many questions can I answer? I'm in a hurry. I'm in a hurry. I'm in a hurry. I'm in a hurry


Because there are six possible results of any natural number divided by 6: 0, 1, 2, 3, 4, 5, and there are seven numbers, which will produce seven residuals. Then at least two of the seven residuals are the same. If you find the difference between the two numbers, you can just subtract the residuals, and the result can be divided by 6



Who can help to solve the following problem (Grade 6)
There are 630 tons of sand in two piles. If two fifths of the sand in pile a is put into pile B, the sand in pile B is four times as much as that in pile A. how many tons of sand are there in each pile?
There is also a small question:
Find the rules and fill in the numbers
1/2 ,1/6 ,1/12 ,1/20 ,1/30 ,1/42 ,( ),( ),( )


Suppose: there were x tons of sand in pile a, then there were (630-x) tons of sand in pile B, 2 / 5x + (630-x) = 4 * 3 / 5xx = 210630-210 = 420 tons, so the sand in pile a was 210 tons, and the sand in pile B was 420 tons



A few sixth grade practical problems, the best distribution
1. The volume of an original book is 50.24 cubic meters, and the perimeter of its bottom is 15.7 meters. How high is the column?
2. A cuboid refrigerator, 4 decimeters long, 3 decimeters wide and 5 decimeters high, is filled with water. Pour the water into a cylindrical bucket, 12 decimeters high, with 2 / 5 of the space in the bucket. How many square decimeters does the cylindrical bucket cover?
3. The side of a cylinder is a rectangle with a length of 25.12 cm and a width of 5 cm. What is the maximum volume of the cylinder?


1. Radius of bottom circle: 15.7 △ 3.14 △ 2 = 2.5m
The area of bottom circle: 2.5 × 2.5 × 3.14 = 19.625m & sup2;
Height: 50.24 △ 19.625 = 2.56M
2. Water volume: 4 × 3 × 5 = 60dm & sup3;
Barrel volume: 60 △ 2 / 5 = 150dm & sup3;
The floor area of the barrel: 150 △ 12 = 12.5dm & sup2;
3. If the circumference of the bottom is 25.12cm, 5cm is the height of the cylinder
Bottom circle radius: 25.12 △ 3.14 △ 2 = 4cm
Cylinder volume: 4 × 4 × 3.14 × 5 = 251.2cm & sup3;
② Taking 5cm as the circumference of the bottom surface, 25.12cm is the height of the cylinder
Radius of bottom circle: 5 △ 3.14 △ 2 = 2.5 / 3.14cm
Cylinder volume: 2.5 / 3.14 × 2.5 / 3.14 × 3.14 × 25.12 = 50cm & sup3;
Because 251.2cm & sup3; > 50cm & sup3;
So the largest volume of this aid is 251.2cm & sup3;