(p-q)^4÷(q-p)^3 · (p-q)² (-3a)^3-(-a) · (-3a)^2 4-(-2)^-2-3²÷(3.14-π)^0 (-1/3)^-2+(1/9)^0+(-5)^3÷(-5)² (-10)^3×(2×10^-5)^0-(1/10)^-2×10×2 x^m · (x^n)^3÷(x^m-1 · 2x^n-1) (b-a)(b-a)^3(a-b)^5 (a-b) ^ 5m (B-A) ^ 2m ÷ (B-A) ^ 7m (M is even, a ≠ b) [(n-m)²]^p · [(m-n)(m-n)^p]^5

(p-q)^4÷(q-p)^3 · (p-q)² (-3a)^3-(-a) · (-3a)^2 4-(-2)^-2-3²÷(3.14-π)^0 (-1/3)^-2+(1/9)^0+(-5)^3÷(-5)² (-10)^3×(2×10^-5)^0-(1/10)^-2×10×2 x^m · (x^n)^3÷(x^m-1 · 2x^n-1) (b-a)(b-a)^3(a-b)^5 (a-b) ^ 5m (B-A) ^ 2m ÷ (B-A) ^ 7m (M is even, a ≠ b) [(n-m)²]^p · [(m-n)(m-n)^p]^5




Practical problems in junior high school
A starts from 8 a.m. and walks 4.5 kilometers per hour. B starts from 9:30 a.m. by bike and meets a 5 / 2 hour later. How fast is B going?


4.5*(1.5+2.5)+2.5x=50
x=12.8



A calculation problem
2008 times 98 and a quarter minus 225 times 10 and a quarter plus 200 and a quarter times 28 and a quarter =


2008 × 98 and 1 / 4-225 × 10 and 1 / 25 + 200 and 4 / 5 × 28 and 3 / 4
=2008×98+2008×1/4-225×10-225×1/25+(200+4/5)×(28+3/4)
=2008×(100-2)+502-2250-9+200×28+200×3/4+4/5×28+4/5×3/4
=200800-4016+502-2259+5600+150+22.4+0.6
=200800-4016-2259+502+5600+150+23
=200800-6275+6275
=200800