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If am = a1a2a3a4a5, then M = () A. 9B. 10C. 11D. 12
According to the properties of the equal ratio sequence, we get that A1 · A5 = A2 · A4 = A32, and am = a1a2a3a4a5, so am = A35, because am = a1qm − 1 = qm-1, A3 = a1q2 = Q2, so qm-1 = (Q2) 5, so M-1 = 10, that is, m = 11, so C
If am = a1a2a3a4a5, then M = ()
A. 9B. 10C. 11D. 12
According to the properties of the equal ratio sequence, we get that A1 · A5 = A2 · A4 = A32, and am = a1a2a3a4a5, so am = A35, because am = a1qm − 1 = qm-1, A3 = a1q2 = Q2, so qm-1 = (Q2) 5, so M-1 = 10, that is, m = 11, so C
If am = A1, A2, A3, A4, A5, then M is equal to?
If an equals A1 times A2 times A3 times A4 times A5, what is n equal to
An is equal to the fifth power of A1 times the (1 + 2 + 3 + 4) power of Q
Because A1 = 1, we can calculate n = 11 according to the formula
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