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If am = a1a2a3a4a5, then M = () A. 9B. 10C. 11D. 12
According to the properties of the equal ratio sequence, we get that A1 · A5 = A2 · A4 = A32, and am = a1a2a3a4a5, so am = A35, because am = a1qm − 1 = qm-1, A3 = a1q2 = Q2, so qm-1 = (Q2) 5, so M-1 = 10, that is, m = 11, so C
If the first term of {an} is A1 and the common ratio is Q, then its recurrence formula is an + 1=______ The relationship between an and am is an=______
If the first term of {an} is A1 and the common ratio is Q, then its recurrence formula is an + 1=______ ；
The relationship between an and am is an=______
an+1=a1*q^n
an=am*q^(n-m)
Is am * an equal to a (M + n)?
Note: it is an equal ratio sequence
Am=A1*q^(m-1)
An=A1*q^(n-1)
A(m+n)=A1*q^(m+n-1)
Am * an / a (M + n) = A1 / Q, A1 is not necessarily equal to Q, so am * an is not necessarily equal to a (M + n)?
RELATED INFORMATIONS
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- 9. Given that 12 < m < 60, and the equation x ^ 2-2 (M + 1) x + m ^ 2 = 0 about X has two positive tree roots, find the value of integer m, and find the two integer roots of the equation It is known that 12 < m < 60, and the equation x ^ 2-2 (M + 1) x + m ^ 2 = 0 about X has two integer roots. Find the value of integer m, and find the two integer roots of the equation (I'm sorry, I wrote the wrong question to correct it.)
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- 11. If am = a1a2a3a4a5, then M = () A. 9B. 10C. 11D. 12
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