If the lengths of two parallel chords are 6cm and 8cm respectively in a circle with a radius of 5cm, the distance between the two chords is______ .

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There are two cases: ① when AB and CD are on the same side of O, as shown in Figure 1,
O as OE ⊥ AB in E, Cd in F, OA, OC,
∵AB∥CD，
∴OF⊥CD，
According to the vertical diameter theorem, AE = 1
2AB=3cm，CF=1
2CD=4cm，
In RT △ OAE, from Pythagorean theorem, OE is obtained=
OA2−AE2=
52−32=4（cm）
Similarly, of = 3cm is obtained,
EF=4cm-3cm=1cm；
II.
When AB and CD are on both sides of O, as shown in Fig. 2, OE = 4cm, of = 3cm can be obtained by the same method,
Then EF = 4cm + 3cm = 7cm;
The distance between AB and CD is 1cm or 7cm,
Therefore, C

In the circle O with a radius of 5cm, the length of chord AB is 5 and the number is 2cm

Cutting fan area s = 5 ^ 2 * 3.14 / 4-2 * 5 = 9.625

AB is the diameter of circle O, chord CD is perpendicular to AB, e is perpendicular to AB, be = 6, AE = 4, what is CD equal to?

AE*EB=CE*ED
Because CE = ed
So CE ^ = 6 * 4 = 24
CD = 2ce = 2 * 2 root number 6 = 4 root number 6

AB is the diameter of circle O, CD is the chord of circle O. the two chords intersect at point E and the included angle is 30 degrees, AE = 1, be = 5. Find CD

Hungry,
Connect OD, do om vertical CD,
AE = 1, be = 5, so radius = od = 3, OE = 2
Because the angle OEM is 30 degrees and the angle OMC is a right angle,
So om = 0.5, OE = 1
Because od = 3, OM = 1, and it is a right triangle,
So using Pythagorean theorem, we get DM = 2, radical 2,
So CD = 2Md = 4 root sign 2

AB is the diameter of circle O, CD is the chord perpendicular to e, AE = 9, be = 1, CD =?

ae=9,be=1
ab=10
The radius is five
So OE = 5-1 = 4
connect oc.od
CE squared = OC squared - OE squared = 25-16 = 9
ce=3
Also, ed = 3 can be obtained
So CD = CE + ed = 3 + 3 = 6

The diameter ab of the circle O intersects with the chord CD at the point E. we know that AE = 1cm, EB = 5cm, CD = 2, root number 6cm. Find the degree of ∩ DEB It's limited to tomorrow morning,

Let the midpoint of CD be m and connect to OM
∵AE+EB=AB=1+5=6
∴0A=OD=1/2AB=3
∵ om vertical bisection CD
∴OM=√[OD²-(CD/2)²]=√3
∵OA=3,AE=1
∴OE=2
∴EM=√(OE²-OM²)=1
∴∠EOM=30°
∴∠DEB=60°

As shown in the figure. Given the diameter of ⊙ o, AB and chord CD intersect at point E, AE = 1cm, be = 5cm, ∠ bed = 60 ° and find the length of ED

Connection OD, EO = 2, OD = 3, ∠ bed = 60 °
According to the cosine theorem, there are
(ED^2+EO^2-OD^2)/(2EO*ED)=COS60=1/2
By substituting the numerical value into, we can get the following results:
Ed = 1 + root 6 or 1 - root 6
The length should be a positive number, so Ed = 1 + root 6

As shown in the figure circle, two chords AB and CD intersect at point E, AE = 6, be = 4, de = 8, and find the length of CE

CE=3
Connecting AC, BD
The △ ace and △ BDE are similar
So the corresponding edges are proportional
CE / be = AE / De
That is, CE / 4 = 6 / 8
CE=3

If the lengths of two parallel chords are 6cm and 8cm respectively in a circle with a radius of 5cm, the distance between the two chords is______ .