![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
As shown in FIG. 12, AOB is a straight line, OE bisection of AOC, of bisection of BOD, ∠ cod = 30 ° and try to find the degree of ∠ EOF
∠AOC+∠BOD=180°-∠COD=150°
∠AOC=2∠AOC+∠BOD ∠BOD=2∠FOD
∠AOC+∠BOD=2(∠EOC+∠FOD)=150°
∠EOC+∠FOD=75°
∠EOF=∠EOC+∠COD+∠FOD=75+30=105°
How to cut a hexagon with the largest area in a square with 1.5m side length What is the side length
The square ABCD is connected with AC, and the center is o. take the point e to make the angle AOE be 60 degrees. OE is the maximum radius of the regular hexagon circumscribed circle, and the length is equal to its side length
Given that the area of regular hexagon is 1, find the area of inscribed circle Given that the area of the regular hexagon ABCDEF is 1, find the area of the inscribed circle of the regular hexagon
Connect the center of a regular hexagon with the six vertices
Six triangles are congruent and equilateral
So each area is 1 / 6
It can be found that one side is (2 times root 3) / 3, and the height on one side is (6 times root 3) / 6
The center of a circle is the center of a regular hexagon
So the radius of the circle is the height on any side of the six triangles,
That is: under the root sign (6 times the root number 3) / 6
So s inscribed circle = pie R ^ 2 = (radical 3) / 6 Pai
The radius of the inscribed circle of a hexagon is
This problem is equivalent to finding the height of an equilateral triangle with a side length a. the answer is the root of 2 times 3 times a
The area formula of regular hexagon should be accurate~
If the side length of a regular hexagon is a, you can push its area by yourself: take the center of the regular hexagon and connect it with each other end point. Then the regular hexagon will become six equilateral triangles, and the side length is a
The area of an equilateral triangle is 3 / 4 * a ^ 2, so the area of a regular hexagon is 6 * root 3 / 4 * a ^ 2 = 3 * root 3 / 2 * a ^ 2
The watchtower master adopted it
What is the area formula of regular hexagon?
If the side length of a regular hexagon is a, then its area = (3 (√ 3) a ^ 2) / 2 / x0d if the side length of an equilateral triangle is x, then there is ((√ 3) a ^ 2) / 4 = 12. If (√ 3) (a / 2) ^ 2 = 12 (changed the following type), then the perimeter of a regular hexagon is x / 2, which can be obtained from the area formula of the above formula,
The area calculation formula of hexagon? Easy to understand, I'm only six years old!
If it is a regular hexagon, it can also have a formula. If it is a random hexagon, it is generally treated with cut and complement method
Find the area formula of regular hexagon! Find the area formula of regular n-polygon
S regular hexagon = 6 * 1 / 2 * r * rsin60 ° = √ 3 / 2R ^ 2
S positive n-polygon = 1 / 2 * NR ^ 2Sin (360 / N)
How to calculate the area of a regular hexagon with a side length of 6?
A regular hexagon is divided into six equilateral triangles with a length of 6 by connecting its center with its six vertices. The area of a regular hexagon is the sum of the areas of six equilateral triangles, and the area of each equilateral triangle is 1 / 2 × 6 × 6 × sin60 = 18 × (√ 3 / 2) = 9 √ 3 ν the area of a regular hexagon = 9 √ 3 × 6 = 54 √ 3
The area of regular triangle and regular hexagon with side length a (a > 0) is calculated respectively
Area formula of regular triangle
S=a*√3a/2/2
Area formula of regular hexagon
S=2a*√3a/2/2+a*a
RELATED INFORMATIONS
- 1. The surface area of regular hexagon is 12 If it is divided into six regular triangles, Is an equilateral triangle?
- 2. The ratio of the three sides of a triangle is 2:4:5. The longest side is 6cm longer than the shortest side. Find out the circumference of the triangle with the equation
- 3. If an equilateral triangle is a meter long, its circumference is () meters
- 4. 0
- 5. A square with a side length of 6.28 cm has a circumference equal to that of a circle. The diameter of the circle is () cm and the area is () square centimeter
- 6. Compare the size of the 18th power of 2 × the 10th power of 3 and the 10th power of 2 × 3 of the 15th power
- 7. Last 100 bits of PI
- 8. Who has the PI accurate to 1 to 100?
- 9. Within a circle, the ratio of the diameter of a circle to its circumference is called PI Pay attention to the questions. I used to type X on the test paper, but many people check √, so I want to have a look My understanding: "the ratio of the diameter of a circle to the circumference of a circle" is wrong. It should be "the circumference of a circle and the diameter of a circle"! Thank you for helping me to answer the friend!
- 10. Relating to the PI and the circumference of a circle The circumference of a circle = Pi times d or 2 times R. are these two formulas? Are they used to calculate the circumference? If so, then I understand the first formula It's PI times diameter The second one doesn't understand 2 times the radius? 2 times the radius. I understand. It's the diameter and then the circumference But what does the multiplication radius of the 2-fold school represent? What is the multiplication of two 3.14? What does it represent? In addition, what does the PI represent? What is the relationship between PI and radius, diameter and circumference? Please give an example to illustrate What does circumference apart from diameter represent?
- 11. 0
- 12. It is known that in △ ABC, CA = CB, ∠ C = 90 ° D is any point on AB, AE ⊥ CD, perpendicular foot is e, BF ⊥ CD, and vertical foot is F. it is proved that EF = | ae-bf |
- 13. As shown in the figure, in △ ABC, ab = AC, ∠ BAC = 120 ° and EF is the vertical bisector of ab. EF intersects BC at point F and ab at point E. verification: BF = 1 2FC．
- 14. Two equal line segments AB and CD coincide in one third. M and N are the midpoint of AB and CD respectively. If Mn = 12cm, find the length of ab
- 15. In the hexagon ABCDEF, ∠ a = ∠ D, ∠ B = ∠ e, ∠ C = ∠ F, try to guess the position relationship between AF and CD, and explain the relationship
- 16. AB is the diameter of the circle, the radius OC ⊥ AB, the chord EF is parallel AB through the midpoint D of OC. It is proved that the angle Abe is equal to 15 ° and the angle CBE is equal to 30 °
- 17. 0
- 18. As shown in the figure, the radius of ⊙ o is known to be 1, De is the diameter of ⊙ o, the tangent of ⊙ o is ad, C is the midpoint of AD, AE intersects ⊙ o at point B, and the quadrilateral bcoe is a parallelogram (1) Find the length of AD; (2) Is BC tangent to ⊙ o? If so, give proof; if not, give reasons
- 19. As shown in the graph, points D, e and F are the points on the edges BC, Ca and ab of the triangle ABC, De is parallel to Ba, DF is parallel to Ca, and it is proved that ∠ FDE = ∠ a
- 20. As shown in the figure, it is known that AB is parallel to CD, OA = OD, BC passes through point O, e, f are on the straight line AOD and AE = DF