As shown in the figure, AB and CD are the two parallel chords in the circle O, M is the midpoint of AB, and the extension line of DM intersects the circle O at e. it is proved that O, m, e and C are in the same circle

As shown in the figure, AB and CD are the two parallel chords in the circle O, M is the midpoint of AB, and the extension line of DM intersects the circle O at e. it is proved that O, m, e and C are in the same circle

Connect EC, OC, OD, Mo and extend Mo to n
Then the angle e = angle COD / 2 = angle con, so o, m, e, C are in the same circle
Conclusion

As shown in the figure AB is the diameter of circle O and CD is the chord. Through C and D, we make CN vertical CD, DM vertical CD, respectively, and cross AB to n M. are an and BM equal

Because 0 is the center of the circle, CD is two points on the circle. So OC = OD, both are radius. Triangle OCD is isosceles trapezoid. Make the height of CD side, this height must be perpendicular to CD. So it is parallel to MD and NC

Given the fixed point a (- 2,0), the moving point B is a point on the Circle F (X-2) ^ 2 + y ^ 2 = 64 (F is the center of the circle), and the vertical bisector of line AB intersects BF at P.1. Then the trajectory equation of moving point P is 2. The locus of point P intersected by the straight line y = √ 3x + 1 is at M and N. if there is a point C on the trajectory of point P, it is vector om + vector on = m times vector OC, and the value of real number m is?

If the moving point P is an ellipse focusing on a f, then 2A = 8, C = 2, B ^ 2 = a ^ 2-C ^ 2 = 12, then the trajectory equation of the moving point P is x ^ 2 / 16 + y ^ 2 / 12 = 12. Let m (x1, Y1) n (X2, Y2) C (x, y) replace the straight line y = √ 3x + 1 into

The coordinates of point a are known to be (- 1) B is a circle F: (x-1) 2) 2 + y2 = 4, the vertical bisector of segment AB intersects BF at P, then the trajectory of moving point P is () A. Circle B. Ellipse C. A branch of hyperbola D. Parabola

From the meaning of the title, | PA | = | Pb |,
∴|PA|+|PF|=|PB|+|PF|=r=2>|AF|=1
The locus of point P is an ellipse focusing on a and F
Therefore, B

The coordinates of point a are known to be (- 1) B is a circle F: (x-1) 2) 2 + y2 = 4, the vertical bisector of segment AB intersects BF at P, then the trajectory of moving point P is () A. Circle B. Ellipse C. A branch of hyperbola D. Parabola

From the meaning of the title, | PA | = | Pb |,
∴|PA|+|PF|=|PB|+|PF|=r=2>|AF|=1
The locus of point P is an ellipse focusing on a and F
Therefore, B

There is a point P (1,1) in the circle (x-1) ^ 2 + y ^ 2 = 4. AB passes through the point P. if the chord length AB = 2 and the root sign 3, then the square of the line

According to the problem, the distance from the center of the circle to the straight line is 1, and the slope of the line exists
Let the slope be K, then the equation is y = K (x-1) + 1 / √ (1 + k?) = 1
Then k = 0 and the equation is y = 1

In a circle of radius 3, there is a chord ab of length 3. Find the length of the arc to which chord AB is opposite What is the length of the arc

Because the radius is 3 and the chord length is 3, then AOB is an equilateral triangle. Then the angle of the center of the circle to which chord AB is opposite is 60 degrees, that is π / 3
Then the length of the arc is the center angle × radius = π

As shown in the figure, in ⊙ o, AB=2 CD, try to judge the relationship between AB and CD, and explain the reason

AB<2CD.
take
If the midpoint e of AB connects EA and EB, then
EA=
EB=
CD,
So EA = EB = CD,
In △ Abe, AE + be > AB, i.e., 2CD > ab,
Then AB < 2CD,
∴CD<AB<2CD.

In a circle with radius 9, there is a chord ab of length 9. What is the length of the arc that chord AB is opposite to

One sixth of the circumference
nine point four two

In a circle O of radius 10, the length of chord AB is 10 (1) Find the size of the central angle α of the circle to which the string AB is opposite; (2) Find the arc length L of the sector where α is located and the area s of the arc

(1) From the radius of ⊙ o = 10 = AB, we know that ⊙ AOB is an equilateral triangle,
∴α=∠AOB=60°=π
3.
(2) According to (1), α = π
3, r = 10, ν arc length L = α· r = π
3×10=10π
3,
/ / s sector = 1
2lr=1
2×10π
3×10=50π
3,
And s △ AOB = 1
2•AB•10
Three
2=1
2×10×10
Three
2=50
Three
2,
ν s = s sector-s △ AOB = 50 (π
3−
Three
2).