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=The second power of 4A (a + 4) = 2A + 4

（1） Square of Y=2x -2 X ∈ * (- ∞ *0) (2) cube of y= radical 2x+1 x ∈ * (0+ ∞) known set A= {(x*y) Finding the inverse function of a function

1)Y=2X^2-2
X=√1/2(Y+2)
The inverse function is y = √ 1 / 2 (x + 2)
2)y=(√2x+1)^3
x=(y^2/3-1)/2
The inverse function is y = (x ^ 2 / 3-1) / 2

Simplify the cube radical X of a/1 radical x/1

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﹣√﹙﹣a﹚＋√﹙﹣a﹚³－a√﹙﹣1/a﹚
＝﹣√﹙﹣a﹚－a√﹙﹣a﹚＋√﹙﹣a﹚
＝﹣a√﹙﹣a﹚.

1 / 2 × cube root 27 / 19-1 + root 1 / 36 13 process

1 / 2 × cube root 27 / 19-1 + root 1 / 36 13
=1 / 2 × cube root (- 8 / 27) + root (49 / 36)
=1 / 2 × (- 2 / 3) + 7 / 6
=-1 / 3 + 7 / 6
=Five out of six

Given that y = radical X-2 + Radix 2-x + 3, try to find the cube root of the x-th power of Y

x-2>=0
2-x>=0
∴x=2
When x = 2, y = 3
∴y^x=3²=9

Let n be a positive integer and the 2n power of x = 3, find the value of the 2nd power of (2x to the 3N power) + (- 3x to the 2n power)

(2n power of 2x) 2 ＋ (- 2n power of - 3x) 3
=4 [2n power of x] 3 - 27 [2n power of x]
=- 23 [2n power of x] 3
=－23×6³
=－4968

Note: it is under the root (2 minus root 3)

[√（2-√3）×√（2+√3）]＾2012
={√[（2-√3）×（2+√3）]}＾2012
=[√（2²-√3²）]＾2012
=[√（4-3）]＾2012
=1＾2012
=1

If a and B are opposite numbers to each other, C and D are reciprocal of each other, | m | = 4, find the value of 2A - (CD) 2010 + 2b-3m

∵ A and B are opposite numbers to each other,
∴a+b=0，
∵ C and D are reciprocal,
∴cd=1，
∵|m|=4，
∴m=±4，
When m = 4, 2A - (CD) 2010 + 2b-3m = 2 × 0-12010-3 × 4 = - 1-12 = - 13,
When m = - 4, 2A - (CD) 2010 + 2b-3m = 2 × 0-12010-3 × (- 4) = - 1 + 12 = 11

If the square of the absolute value of x-3 + (Y-3) equals 0, what is the x-th power of Y ..

Because | x-3 | > = 0, (Y-3) ^ 2 > = 0
So let | x-3 | + (Y-3) ^ 2 = 0
Then | x-3 | = 0, x = 3
(Y-3) ^ 2 = 0, y = 3
therefore
Y^x
=3^3
=27
I hope it can help you. If you have any questions, please ask,