2011 ^ 2-2012 * 2011 =? (calculated by square difference formula)

2011 ^ 2-2012 * 2011 =? (calculated by square difference formula)

Original formula = 2011 2 - (2011 + 1) (2011-1)
=2011²-(2011²-1)
=1

If the root X-8 + 1 / 8-x is meaningful, then the cube root of X is equal to ()

x-1/8≥0
x≥1/8
1/8-x≥0
x≤1/8
So x = 1 / 8
The cube root of X is equal to (1 / 2)

Compare the size of a = root number 2012 - root number 2010 and B = root number 2011 - root number 2009

Hypothesis √ 2012 - √ 2010

Calculation: under the root sign (16 and 16 of 25)

3.2. There is a special calculator in app

In the set composed of real number x, - x, absolute value x, root sign x square, - root sign x cubic power, the maximum number of elements is I hope the accuracy is high

Three

The process and answer of finding the root 1 and 2 / 3 divided by the root 6 / 5

Radix 1 and 2 / 3 △ Radix 5 / 6
=Root 5 / 3 * root 6 / 5
=Radical 2

The square root a minus 2012 / 2011 equals to the square of - 6 (B plus 1 / 2012) and the value of 1 / 1006 of a + B + 1006

Because the root sign (a-2012 / 2011) > = 0
6 (B + 1 / 2012) 2 > = 0, so - 6 (B + 1 / 2012)

Sin 40 O + sin 50 o (1 + Tan 10 o of 3 times the root number) divided by [sin 70 o multiplied by {root number}

The title is incomplete. How many times?
In fact, the key point of this topic is the angle conversion 50 ° = 90 ° - 40 ° 70 ° = 40 ° + 30 °
There is also the addition and subtraction of trigonometric function 1 + √ 3tan10 ° = (tan60 ° - tan10 °) / Tan (60 ° - 10 °)
Will the rest of the building owners do it?

[cos40＋sin50(1＋√3tan10)]/sin70√(1＋cos40)

Molecular cos40 + sin50 (1 + √ 3tan10) = cos40 + sin50 (cos10 + √ 3sin10) / cos10 = cos40 + sin50 * 2sin40 / cos10 = cos40 + sin80 / cos10 = cos40 + 1 = 2 (cos20) ^ 2
denominator
sin70√(1+cos40)=sin70√2cos20=√2(cos20)^2
Therefore, the original formula = √ 2

In △ ABC, the opposite sides of angles a, B and C are a, B, C respectively, and Sina / a = √ 3cosc / C. (1) find the size of angle C (2) If a + B = 6, vector ca * vector CB = 4, find the value of C

(1) If a + B = 6, vector ca * vector CB = 4, then we get two equations: a + B = 6, the absolute value of COSC x a, the absolute value of x B = 4