Sina = (4-2m) / (M + 5), cosa = (M-3) / (M + 5) and a is the fourth quadrant angle to find Tana

Sina = (4-2m) / (M + 5), cosa = (M-3) / (M + 5) and a is the fourth quadrant angle to find Tana

Sina0 is the fourth quadrant angle sina0 and (Sina) ^ 2 + (COSA) ^ 2 = 1 [(4-2m) / (M + 5)] ^ 2 + [(M-3) / (M + 5)] ^ 2 = 1 (4-2m) / (M + 5)] ^ 2 = 1 (4-2m) / (M + 5)] ^ 2 = 1 (4-2m) / (M + 5)] ^ 2 = 1 (4-2m) / (M + 5)] ^ 2 = 1 (4-2m) / (M + 5) / (M + 3) / (M + 5), then M = M = 8, if M = 8, then M = 8, if Sina = (4-2m) / (M + 5) and cosa = (M-3) / (M + 5), then M = M = M = M = 3) / (8 characters

Given that the absolute value of 3x minus 2 and the absolute value of Y minus 2 is equal to 0, find the absolute value of 6x minus y Analyze the process Given that l3x-2l + ly-2l = 0, find the value of l6x YL.

Because l3x-2l + ly-2l = 0,
So 3x-2 = 0 and Y-2 = 0,
That is, x = 2 / 3, y = 2,
Therefore, l6x YL = | 6 * (2 / 3) - 2| = 2

Find the polar coordinates of (2, - radical 3) in rectangular coordinate system RT

Point a (2, - 3) is in the fourth quadrant,
r=OA=√7,
rcosθ=2,θ=-arccos[（2√7）/7],
The polar coordinates of √ arc2 and arc2 are √

Y = (2x-1) / (x + 1), x > 1

y=(2x-1)/(x+1),x>1
x=(y+1)/(2-y)
X>1
(y+1)/(2-y)>1
When 2-y > 0
y>1/2
When 2-y < 0
(y+1)/(2-y)<1
Y < 1 / 2 is not consistent with Y > 2
therefore
The range of Y is (1 / 2,2)

If the root x is a real number, then y = the square of X + 3 * X-5?

Y = the square of X + 3 * X-5?
=x^2+3x-5
=(x+3/2)^2-9/4-5
=(x+3/2)^2-29/5
So when x = - 3 / 2, y takes the minimum of - 29 / 5
So the range is [- 29 / 5, positive infinity)

() is obtained by shifting the factor other than (A-1) × 1/a-1 radical minus the radical into the radical

-1/(a-1)>0
So A-1

The length of X and D of the line segment passing through the X and D of the line segment is the X and D of the second order of the image 1. Find the analytic formula of quadratic function

Because the abscissa of vertex C is 4, the length of segment AB cut on the x-axis of the image is 6,
So the intersection point of parabola and X axis is (1,0) (7,0)
Let the parabola be y = a (x-1) (X-7),
Replace D (0,7 / 9 root sign 3) with,
7A = 7 / 9 root number 3,
A = (1 / 9) root sign 3,
So the analytic formula of quadratic function: y = (1 / 9 radical 3) (x-1) (X-7)

We know that the symmetry axis of the parabola y = x + BX + C is x = - 1, and the X axis intersects at the point AB, the vertex of AB is m and s △ mAb = 2 times the root sign 2

The symmetry axis X = -b / 2 = -1, so B = 2; parabola and X-axis have intersection points, which shows that x ^ 2 + BX + C = 0 has a solution, that is, X1 + x2 = - B / 1 = -2; X1 * x2 = C / 1 = C [Veda theorem] root discriminant of 4-4c > 0, C < 1s = 1 / 2 * lx1-x2l * H = 2 √ 2, H = will X-1-1 into the parabola value = C-1, lx1-x2l = √ [(x1 + x2) ^ 2-4x1x1x2] = (4 * 4 * 4 * 4) = (4) 4 (4) C > 0, C < 1, s = 1 = 1 / 1 * 1 * 1 = 1, lx1-x2l = (x1 + x2) ^ 2-- 4C), 1 / 2 * √ (4-4c) * lc-1l = 2 √ 2, Question: x = - B / 2 = - 1 shouldn't be - 2A B? This is the question of finding function expression. Title: the symmetry axis of parabola y = x + BX + C is a straight line x = - 1, which intersects with X axis at two points a and B, the vertex is m, and the area of △ mAb is s = 2 √ 2 2. Because the parabola and X-axis intersect at a and B points, the equation f (x) = x + 2x + C = 0 has two different roots: the discriminant formula △ = 4-4c > 0, then C < 1; 3. The area of △ mAb is known, then in △ mAb, if ab edge is the bottom, then the bottom edge length AB = | x1-x2 | (2 ͱ (4-4c), x = (4-4c), x = x = (4-4c), high x = = = (4-4c), high x = = = (4-4c), high x = = =, x =, X = (4-4c), high x = =, x =, x =, x = (4-4c), x = (4-4c), x = (4-The absolute value of the function value at - 1 |F (- 1) | = 1-C; s = ab ×| f (- 1) | / 2 = 2 √ 2, the square of both sides, that is (4-4c) (C-1) / 4 = 8, the solution is 1-C = 2, C = - 1. Therefore, the analytic formula is y = x + 2x - 1. Thank you. Answer: students, adopt Oh, follow up: there must be rewards. Answer: study hard, enter university, serve the motherland

The cubic power of X + the square of 2x + the square of XY under the radical sign - the reduction of the square of 4x + the square of 4xy + the cubic power of Y under the radical sign

simple form
=Under radical sign [x (x + y) ^ 2] - under radical sign [y (2x + y) ^ 2]
=Under (x + y) radical sign x - (2x + y) radical sign Y

-The third power of root 27 - (the third power of root - 1) + root 225 - root 625

=-3-(-1)+15-25
=-3+1+15-25
=-12