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Find the inverse function of the function y = LG (x + 2). (write the process of solving the problem)
If y = LG (x + 2), (R) is the value range of ﹥ and the exponential function with the base of 10 is taken on both sides, then, 10 ^ y = x + 2, x = 10 ^ Y-2, the inverse function is y = 10 ^ X-2 (x > R)
Solving the equation x / 2x - 5 / 5 - 2x - 2x = 1 simplification: 2x / x + 3-x + 2
Please put the numerator or denominator in brackets so that I can answer
The definition domain of the inverse function of the function f (x) = 3x + 1 / X-1 is
f (x)=(3x+1)/(x-1)
=((3x-3)+4) /(x-1)
=3+4 /(x-1)
Because 4 / (x-1) ≠ 0, f (x) ≠ 3
So the range of function is {y | y ≠ 3}
The definition domain of inverse function is the range of original function
The definition domain of inverse function is {x | x ≠ 3}
If f (x) = 3x, then the domain of definition of the inverse function F-1 (x) of F (x) is
The definition domain of inverse function number is the range of original function number,
So the definition domain of the inverse function F-1 (x) is [0, + ∝)
Find the definition domain of inverse function of function y = x ^ 22 (x ≥ 0)
The definition domain of inverse function is the range of original function
y=x^2 (x≥0)
y≥0
So the definition domain of inverse function is x ≥ 0
If the definition domain of the function y = f (x) is (- ∞, 0), and f (x + 1) = x ^ 2 + 2x, then its inverse function=__ , whose domain is__ . f^(-1)(x)=?
f(x+1)=x^2+2x=x^2+2x+1-1=(x+1)^2-1
f(x)=x^2-1
x= ±√y+1
The domain of y = f (x) is (- ∞, 0),
So the inverse function is f (x) = - √ x + 1 x ∈ (- 1, + ∞)
Find the inverse function of the function y = 2x + 1 (x is a real number), and write the definition domain of the inverse function
X = 1 / 2y-1 / 2, y = 1 / 2x-1 / 2, defining domain R
y=x2-2x+1(-1 Math homework help users 2017-09-19 report Use this app to check the operation efficiently and accurately!
Just change y of original function to X and X to y
So the result is: x = y * y-2y + 1 = (Y-1) ^ 2 (- 1 so 0
Homework help users 2017-09-19
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(1) The domain of the inverse function of. F (x) = 1 + 3 ^ X-2 is (2). Log2 (- x)
Since 3 ^ (X-2) > 0, its domain is (1, positive infinity)
2, we know that - x > 0,
And if - x > = 1, x + 1 > 0
So the solution is - 1
If the function y = - radical X-2 (x ≥ 2), find its inverse function
The inverse function is y = x ^ 2 + 2 (x > 0)
Remember that the inverse function and the original function are symmetric with respect to y = X. to find the inverse function of a function is to exchange X and Y in the original function to obtain y =?. the definition domain of the inverse function is the value range of the original function
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