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In the function y equal to the root of (x-1) cent (3-x), what is the value range of the independent variable x?
Denominator is not 0
So x - 1 ≠ 0
So x ≠ 1
The number in the root sign is greater than or equal to 0
So 3 - x ≥ 0
So x ≤ 3
So x < 1 or 1 < x ≤ 3
The function y is equal to the value range of the independent variable x in the root 3-x + x-4
y=√(3-X)+1/(X-4)
The value range of independent variable x satisfies: 3-x ≥ 0 x ≤ 3 (1)
(X-4)≠0 x≠4 (2)
The value range of the independent variable x is (- ∞, 3]
Known function y= x−1 X − 2, and the value range of the independent variable x is______ .
To make the function f (x) meaningful, then
x−1≥0
x−2≠0 ，
The solution is x ≥ 1 and X ≠ 2,
So the answer is: {x | x ≥ 1 and X ≠ 2}
The value range of the independent variable X of the function y equal to the root x minus one
Greater than or equal to 0 under root sign
x-1≥0
x≥1
In the function y equals to the root of 3x, x plus 4, the value range of the independent variable x is——
X is greater than or equal to minus 4
The function y = radical (x-a) has a common point with the image of its inverse function
When the two function images are tangent, the common point is (1 / 2,1 / 2), and a = 1 / 4
When a > 1 / 4, the two function images have no common points
When a
It is known that ⊙ O1 and ⊙ O2 are equal circles and intersect at two points a and B. If ⊙ ao1o2 ≌ △ ao1b, the following conditions should be added____________ one thousand one hundred and eleven
The distance between o 1 and O 2 is equal to the radius of the circle
As shown in the figure, ⊙ O1 and ⊙ O2 intersect at points a and B, and the center of ⊙ O2 is on ⊙ O1, and P is a point on ⊙ O2. Known ᙽ ao1b = 60 °, calculate the degree of ⊙ APB
Take a point C on the superior arc AB of circle O1
Connecting AC, BC
Then the angle c = 30 degrees, the angle ao2b = 150 (circle inscribed quadrilateral, diagonal complementary)
Angle APB = 150 / 2 = 75 degrees
It is known that the circle O1 and the circle O2 are equal circles, and their radii are R1, R2, R1 and R2 are two of the equations 4x2 + ax + 1 = 0 about X, and find the value of A
If the circle is equal, the radius is equal, that is, R1 = R2, that is, the quadratic equation of one variable has two equal positive roots,
△=a^2-16=0
r1+r2=-a/4>0
r1r2=1/4>0
So a = - 4
If two equal circles O1 and O2 of radius R2 are circumscribed, and circle O1 is tangent to AC and AB, and circle O2 is tangent to BC and AB, R2 is calculated Known right triangle ABC, angle ACB is 90 degrees, AC = 6, BC = 8
Suppose that the tangent point of circle O1 and ab is D, the tangent point of circle O2 and ab is e, R2 = R
DE=2*r
AB=AD+DE+EB=10
(r+r*5/4)*4/3+2*r+(r+r*5/3)*3/4=10
It is found that r = 10 / 7
That is, the radius R2 = 10 / 7
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