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In the plane rectangular coordinate system, the point P is above the x-axis, and the distance from the point P to the y-axis is 1, and op = 2, the coordinates of the point P are obtained
Because the distance from P to Y-axis is 1, the abscissa of P is plus or minus 1,
∵ OP = 2, the Pythagorean theorem shows that the distance between P and X axis is √ 3, and because it is above the X axis, P (- 1, √ 3) or (1, √ 3)
In the plane rectangular coordinate system, the midpoint P is above the X axis, the distance from P to y axis is 1, and op = 2, the coordinates of point P are
P (1, radical 3)
The distance from the midpoint a (2, y) to the x-axis in the plane rectangular coordinate system is 3?
The value of Y is 3 or - 3
Given that the point m (x, y) is in the fourth quadrant, the sum of its distances from the two coordinate axes is equal to 17, and the distance from it to the X axis is 3 larger than that from the Y axis. Find x = y=
We can set the equation
Let x = a, y = B, and get B-A = 3 from the meaning of the title
From this, we can get the quadratic equation of two variables
B-A=3
B+A=17
So B = 10
A=7
So x = 7, y = 10
And because it's the fourth quadrant, x = 7, y = - 10
If the distance from point a (2a + 1,3) to the X axis is twice the distance to the Y axis, then a = ()
The absolute value of 2 times (2a + 1) = 3
So a = 1 / 4 or - 5 / 4
Given that the point P is on the x-axis, the distance between the point P and the point m (- 3,4) is equal to the distance between the point P and the point n (- 2,5)
On the x-axis
P(a,0)
PM=PN
That is, PM 2 = PN 2
So (a + 3) 2 + (0-4) 2 = (a + 2) 2 + (0-5) 2
a²+6a+9+16=a²+4a+4+25
A=2
P(2,0)
Given that the distance from the point P (3a-2,4-a) to the x-axis is equal to twice its distance to the y-axis, find the value of a?
Solution: because the distance to the X axis is equal to the y value, and the distance to the Y axis is equal to the x value
When point P is in the first three limits
4-a=2(3a-2)
4-a-6a+4=0
7a=8
a=8/7
In the second and fourth quadrant
4-a=-2(3a-2)
4-a+6a-4=0
A=0
In the plane rectangular coordinate system, if the distance between point a (- 2, - 3) and point B (a, 3-2a) to the X axis is equal, then the value of a is____ .
Equal distance to the X axis means equal absolute Y values
|-3 | = | 3-2a | resolves to a = 0 or 3
In the plane rectangular coordinate system, given that the distance between point A (1-2a, A-2) and two coordinate axes is equal, find the value of a
According to the meaning of the title, 1-2a = ± (A-2)
① When 1-2a = A-2, the solution is: a = 1
② When 1-2a = - (A-2), the solution is: a = - 1
It is known that the distance between point P (1-A, 2A + 5) and two coordinate axes is equal in plane rectangular coordinate system. The value of a is calculated and the coordinates of point P are determined
1-A = 2A + 5, a = - 4 / 3, P coordinate is p (7 / 3,1 / 3)
RELATED INFORMATIONS
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