A cuboid, shortened by 4 meters, becomes a cuboid, reducing the surface area by 120 square meters A cuboid, shortened by 4 meters, becomes a cuboid, and its surface area is reduced by 120 square meters

A cuboid, shortened by 4 meters, becomes a cuboid, reducing the surface area by 120 square meters A cuboid, shortened by 4 meters, becomes a cuboid, and its surface area is reduced by 120 square meters

1. Side length of one surface of shortened part =120÷4÷4=7.5(m)
2. Surface area of residual cube=7.5×7.5×6=337.5(square cm)
3. Surface area of original cuboid=337.5+120=457.5(square centimeter)

What is the surface area of area of 160 square centimeters. What is the surface area of each cuboid after dividing it into two identical cubes? Volume?

The cuboid is divided into two identical cuboids, indicating that the width and height are equal and the length is twice the width.
Suppose the original width is a, the length is 2a, and the height is a
The surface area is 2*a^2+4*2a*a=160
A^2=16===> a=4cm
The resulting cube side length is a
Surface area of cube 6a^2=96 cm2
Volume is a^3=64 cc

The cuboid is divided into two identical cuboids, indicating that the width and height are equal and the length is twice the width.
Let the original width be a and the length be 2a and the height be a
The surface area is 2*a^2+4*2a*a=160
A^2=16===> a=4cm
The side length of the cube is a
Surface area of cube 6a^2=96 cm2
Volume is a^3=64 cc